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Taya2010 [7]
3 years ago
7

Find the values of p and g such that 4x² + 12x = 4(x + p)^2-q

Mathematics
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

q=8xp+4p²-12x

Step-by-step explanation:

its easy

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dimulka [17.4K]

In the Figure below is shown the graph of this function. We have the following function:

f(x)=x^3+2x^2-x-2

The y-intercept occurs when x=0, so:

f(0)=(0)^3+2(0)^2-(0)-2=-2

Therefore, the y-intercept is the given by the point:

\boxed{(0,-2)}

From the figure we have three x-intercepts:

\boxed{P_{1}(-2,0)} \\ \boxed{P_{2}(-1,0)} \\ \boxed{P_{3}(1,0)}

So, the x-intercepts occur when y=0. Thus, proving this:

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7 0
4 years ago
Read 2 more answers
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