Question

40 points need NOW Simplify the expression.

Answer 1

Answer:

$7xy^{2} \sqrt[3]{2xy}$

Step-by-step explanation:

$\sqrt[3]{686x^{4} y^{7}}$

$686 = 343 * 2$

$x^{4} = x^{3} * x$

$y^{7} = y^{3} * y^{3} * y$

$\sqrt[3]{343} =7$

$\sqrt[3]{x^{3}} = x$

$\sqrt[3]{y^{3}* y^{3}}$ = $y^{2}$

so you're left with 2, x, and y inside the cube root, and 7, x, and y^2 outside

$7xy^{2} \sqrt[3]{2xy}$