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egoroff_w [7]
3 years ago
9

Any point on the parabola can be labeled (x,y), as shown. What are the distances from the point (x,y) to the focus of the parabo

la and the directrix? Select two answers.
distance to the focus: (x+3)2+(y−3)2−−−−−−−−−−−−−−−√
distance to the focus: (x−2)2+(y+3)2−−−−−−−−−−−−−−−√
distance to the focus: (x+3)2+(y−2)2−−−−−−−−−−−−−−−√
distance to the directrix: |x−4|
distance to the directrix: |y−4|
distance to the directrix: |y+4|

Mathematics
1 answer:
lapo4ka [179]3 years ago
4 0

Answer:

Step-by-step explanation:

Standard form of the equation:

y  = -\frac{1}{4} (x+3)^2+3

Directrix: y=4

Focus: (-3,2)

Points on the parabola (x,y):

(-5,2) (-3,3) (-1,2)

Distance from points to focus:

(-5,2) = (-3,2)

Answer choices:  (x+3)^2+(y−3)^2, (x−2)2+(y+3)2, (x+3)2+(y−2)2

(-5+3)^2+(2-3)^2=5

(-5-2)^2+(2+3)^2=74

(-5+3)^2+(2-2)^2=4

(-1,2)

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What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!<br><br> Multiply.<br><br> (7x + 3)(4x − 5)
Anni [7]

(7x + 3)(4x -5)

7x*4x+7x(-5)+3*4x+3(-5)

7*4xx-7*5x+3*4x-3*5

7*4xx-7*5x+3*4x-3*5

=28x^2-23x-15

Hope this helps!

Thanks!

-Charlie

3 0
3 years ago
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