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vfiekz [6]
3 years ago
9

Find the gradient of the line segment between the points (-5,2) and (4,3) give your answer in the simplest form

Mathematics
1 answer:
Leokris [45]3 years ago
7 0

Answer: The gradient of the line segment between the points (-5,2) and (4,3) is \dfrac{1}{9}.

Step-by-step explanation:

Formula for gradient of a line segment :

\text{Gradient}=\dfrac{\text{Difference between y-coordinates}}{\text{Difference between x-coordinates}}

Given points of the line segment: (-5,2) and (4,3)

\text{Gradient} =\dfrac{3-2}{4-(-5)}

\text{Gradient} =\dfrac{1}{4+5)}

\text{Gradient} =\dfrac{1}{9}

Therefore , the gradient of the line segment between the points (-5,2) and (4,3) is \dfrac{1}{9}.

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bogdanovich [222]
The area of the square:
a = l²

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7 0
3 years ago
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In a survey of 1000 women age 22 to 35 who work full time, 540 indicated that they would be willing to give up some personal in
morpeh [17]

Answer:

z=\frac{0.54 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=2.530  

p_v =P(Z>2.530)=0.0057  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of women indicated that they would be willing to give up some personal in order to make more money  is significantly higher than 0.5.  

The 95% confidence interval would be given by (0.509;0.571)

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

X=540 represent the women indicated that they would be willing to give up some personal in order to make more money

\hat p=\frac{540}{1000}=0.54 estimated proportion of women indicated that they would be willing to give up some personal in order to make more money

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the majority of woman age 22 to 35 who work full-time would be willing to give up some personal time for more money.:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.54 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=2.530  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.530)=0.0057  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of women indicated that they would be willing to give up some personal in order to make more money  is significantly higher than 0.5.  

Confidence interval

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.54 - 1.96\sqrt{\frac{0.54(1-0.54)}{1000}}=0.509

0.54 + 1.96\sqrt{\frac{0.54(1-0.54)}{1000}}=0.571

The 95% confidence interval would be given by (0.509;0.571)

5 0
4 years ago
What is the remainder when the polynomial f(x)=3x^3-4x^2+2x+8 is divided by (x-5)
yaroslaw [1]

The remainder when the polynomial f(x) = 3x³ - 4x² + 2x + 8 is divided by (x - 5) is constant an equal f(5).

Substitute x = 5 to the polynomial:

f(5)=3(5^3)-4(5^2)+2(5)+8=3(125)-4(25)+10+8\\\\=375-100+18=275+18=293

Answer: (3x³ - 4x² + 2x + 8) : (x - 5) = q(x) + 293.

4 0
3 years ago
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Nookie1986 [14]
You know that a perfect square trinomial is given by square of first term, twice the product of first and last terms and square of second term

So we have x^2 that is square of x, 2x that is twice the product of x*1, the second term shoulf be 1, that is square of 1

So your answer would be 1

If you try (x+1)^2 = x^2+2x+1
3 0
3 years ago
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Which action will solve the equation? m−20=9 Subtract 9 from each side. Add 20 to each side. Subtract 20 from each side. Add 9 t
djyliett [7]

Answer:

m=29

Step-by-step explanation:

add 20 to both sides and that is what m equals

7 0
3 years ago
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