The binomial (2 · x + y)⁷ in expanded form by 128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷.
<h3>How to expand the power of a binomial</h3>
Herein we have the seventh power of a binomial, whose expanded form can be found by using the binomial theorem and Pascal's triangle. Hence, we find the following expression for the expanded form:
(2 · x + y)⁷
(2 · x)⁷ + 7 · (2 · x)⁶ · y + 21 · (2 · x)⁵ · y² + 35 · (2 · x)⁴ · y³ + 35 · (2 · x)³ · y⁴ + 21 · (2 · x)² · y⁵ + 7 · (2 · x) · y⁶ + y⁷
128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷
Then, the binomial (2 · x + y)⁷ in expanded form by 128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷.
To learn more on binomials: brainly.com/question/12249986
#SPJ1
4x + 89.95 = 628.35 <== ur equation
4x = 628.35 - 89.95
4x = 538.40
x = 538.40 / 4
x = 134.60 <== the cost for each cavity filling
Answer:
18 months
Step-by-step explanation:
c
Answer:
The probability that Jason will get exactly 7 strikes out of 10 attempts is 0.117.
Step-by-step explanation:
We are given that Jason is a very good bowler and has proven over the course of a season of league play that he gets a STRIKE 50% of the time.
Also, Jason has been given 10 attempts.
The above situation can be represented through binomial distribution;
where, n = number trials (samples) taken = 10 attempts
r = number of success = 7 strikes
p = probability of success which in our question is % of the time
he gets a strike, i.e; p = 50%
<em><u>Let X = Number of strikes Jason get</u></em>
So, X ~ Binom(n = 10, p = 0.50)
Now, probability that Jason will get exactly 7 strikes out of 10 attempts is given by = P(X = 7)
P(X = 7) =
=
=
= <u>0.117</u>
Therefore, the probability that Jason will get exactly 7 strikes out of 10 attempts is 0.117.