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Ad libitum [116K]
3 years ago
6

Can anyone please help me with this ?

Mathematics
2 answers:
ki77a [65]3 years ago
7 0

Answer:

Distance from point A to the top of the building(hypotenuse)= 5\sqrt{2}feet

Height of the landscaper= 5 feet

Step-by-step explanation:

Given:

Distance from point A to bottom of building = 5 feet

Angle of depression from the top of building = 45°

We see that the triangle formed is a special 45-45-90 right triangle

The sides of such triangle is given by:

Leg1 = x

Leg2=x

Hypotenuse = x\sqrt{2}

We know the  x=5 feet

So we can find all the sides of the triangle:

Leg1 =5 feet

Leg 2 =5 feet

Hypotenuse= 5\sqrt{2}feet

It is shown in figure attached.

Distance from point A to the top of the building(hypotenuse)= 5\sqrt{2}feet

Height of the landscaper= 5 feet

djverab [1.8K]3 years ago
5 0

Answer:

The distance from point A to the top of the building is 5\sqrt{2} feet

The Height of the Skyscraper is 5 feet

Step-by-step explanation:

Given

Let Top point of building be point C

Also Let Base of the building be point  B

Distance from point A to base B of the building AB= 5 feet

∴ It makes a Right angle triangle

Also ∠ACB = 45°

Also tan 45° = 1

Now tan ∠ACB =\frac{AB}{BC}

∴ AB= BC =5 feet

The Height of the Skyscraper is 5 feet

Now Triangle ABC is right angle triangle with right angled at B

So by Pythagoras theorem

AC= \sqrt{AB^2+BC^2}=\sqrt{5^2+5^2} =\sqrt{50} =\sqrt{25\times2} =\sqrt{5^2\times2}=5\sqrt{2}

The distance from point A to the top of the building is 5\sqrt{2} feet

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