Calculate the mean, median, mode, and range for (1, 2, 5, 6, 1, 6, 7)

Toward the middle of the harvesting season, peaches for canning come in three types, early, late, and extra late, depending on the expected date of ripening. During a certain week, the following data were recorded at a fruit delivery station:

34 trucks went out carrying early peaches ;

61 carried late peaches ;

50 carried extra late;

25 carried early and late;

30 carried late and extra late;

8 carried early and extra late;

6 carried all three;

9 carried only figs (no peaches at all) .

<u>To solve this problem, the best solution is to drawn a Venn Diagram, which is attached.</u>

(a) How many trucks carried only late variety peaches?

12

(b) How many carried only extra late?

18

(c) How many carried only one type of peach ?

7+12+18 = 37

(d) How many trucks (in all) went out during the week?

Sum of all the numbers on the Diagram:

7+2+6+19+12+24+18+9= 97

5 0

3 years ago

A student increased in height from 1.52m to 1.68m, calculate the percentage increase (show your working)

Sladkaya [172]

The percentage increase in the student's height is 10.52%.

Here we are given that a student's height increases from 1.52m to 1.68m.

Thus, the absolute increase in the student's height will be-

1.68 - 1.52 = 0.16 meters.

Now, we need to find the percentage increase in the student's height.

The formula for calculating percentage increase is given by-

Percentage increase = change in value/ initial value * 100

Here, the change in value is 0.16 meters and the initial value is 1.52 meters.

Thus, percentage increase in height = 0.16 / 1.52 *100

= 1600/ 152

= 400/ 38

= 200/ 19

= 10.52%

Thus, the increase in the student's height is 10.52%.

Learn more about percentage change here-

https://brainly.in/question/19592355

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6 0

2 years ago