These are 3 questions and 3 answers.
Question 1.
Answer: bot equations have the same potential solutions, but equation A may have extraneous solutions
Explanation:
1) Equation A
Replace x = -4 in the right side of the equation:
Which is not defined, so this is a extraneous solution.
2) Equation B.
Since it is a cube root, it is defined for any (negative, zero, and positive) values of x.
Question 2.
Answer: cubing both sides once.
Explanation:
![\sqrt[3]{5x-2} -\sqrt[3]{4x} =0\\ \\ \sqrt[3]{5x-2} =\sqrt[3]{4x}\\ \\ (\sqrt[3]{5x-2} )^3=(\sqrt[3]{4x})^3\\ \\ 5x-2=4x\\ \\ 5x-4x=2\\ \\ x=2](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B5x-2%7D%20-%5Csqrt%5B3%5D%7B4x%7D%20%3D0%5C%5C%20%5C%5C%20%20%5Csqrt%5B3%5D%7B5x-2%7D%20%3D%5Csqrt%5B3%5D%7B4x%7D%5C%5C%20%20%5C%5C%20%20%28%5Csqrt%5B3%5D%7B5x-2%7D%20%29%5E3%3D%28%5Csqrt%5B3%5D%7B4x%7D%29%5E3%5C%5C%20%20%5C%5C%20%205x-2%3D4x%5C%5C%20%5C%5C%20%205x-4x%3D2%5C%5C%20%5C%5C%20%20x%3D2%20)
3) Question 3.
Answer: c - 2 = 25 + c + 10√c
Explanation:
Since you haven't identified this figure, I'm going to assume that it's a rectangle.
The Perimeter of a rectangle of length L and width W is P = 2L + 2W.
Here you are given the Perimeter and the length, and are to find the width, W.
Solving the above equation for W, we get P - 2L = 2W.
Dividing by 2 (to isolate that W), we get
P
-- - L = W
2
Substitute P= 6 yds and L = 6 feet (or 2 yds), find W (in yards).
Answer:
D
Step-by-step explanation:
Given
x³ + 2x² + 7x + 14 ( factor the first/second and third/fourth terms )
= x²(x + 2) + 7(x + 2) ← factor out (x + 2) from each term
= (x² + 7)(x + 2) → D
Answer:
Step-by-step explanation:
.
10 * 10= 100
7*7=49
the ratio is 100:49
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