Answer:
x
=
72
Step-by-step explanation:
Probability that both roads from a to b are blocked is the product of the individual probabilities, i.e.
P(~ab)=0.25*0.25=0.0625
Similarly
P(~bc)=0.25*0.25=0.0625
Probability that EITHER one or both of ab and bc are blocked is the sum of the probabilities:
P(~ab ∪ ~bc)=0.0625+0.0625=0.125
(recall that one cannot travel from a to c if either ab or bc is blocked.)
Therefore the probability that there exists an open route from a to c
= P(ac) = 1-P(~ab ∪ ~bc)
= 1 - 0.125
=0.875
Answer:
600 minutes
Step-by-step explanation:
If we write both situations as an equation, we get:
y1 = 24 + 0.15x
<em>y1 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>paid </em><em>in </em><em>first </em><em>plan</em>
<em>x </em><em>:</em><em> </em><em>total minutes </em><em>of </em><em>calls</em>
y2 = 0.19x
<em>y2 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>in </em><em>second </em><em>plan</em>
<em>x:</em><em> </em><em>total </em><em>min</em><em>utes </em><em>of </em><em>call</em>
We are now looking for the situation where the total cost in the two plans is equal, so
y1 = y2
this gives
24 + 0.15x = 0.19x
<=> 0.04x = 24
<=> x = 600
Answer:
La cantidad de dinero adeuda al final de los dos procesos es $1450
Step-by-step explanation:
Los parámetros del proceso son;
La cantidad ahorrada para comprar ropa = $2,000
La cantidad pagada por la ropa = $2600
La cantidad prestada a un amigo = $650
La cantidad adeuda por teléfono celular durante 3 meses = $250
Deje que 'C', represente la suma de las transacciones anteriores, tenemos;
∴ C = 2,000 - 2,600 - 650 - 200 = -1,450
La suma de las transacciones anteriores, C = -$1,450
Por lo tanto, al final de los dos procesos, la cantidad de dinero adeuda es C = $1,450
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