Answer:
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Step-by-step explanation:
denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier
then
P(A)= ∑ P(Bi)*P(C) with i from 1 to 3
P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125
from the theorem of Bayes
P(Cz/A)= P(Cz∩A)/P(A)
where
P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained
P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100
therefore
P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Answer:
B
Step-by-step explanation:
Substitute x = h + 2 into f(x), that is
f(h + 2)
= 4(h + 2)² - 17 ← expand factor using FOIL
= 4(h² + 4h + 4) - 17 ← distribute parenthesis and simplify
= 4h² + 16h + 16 - 17
= 4h² + 16h - 1 → B
Answer:
x = (y+w)/k
Step-by-step explanation:
xk-w=y
Add w to each side
xk-w+w=y+w
xk = y+w
Divide each side by k
xk/k = (y+w)/k
x = (y+w)/k
Answer:
d
Step-by-step explanation:
Try using simple numbers like 1 as x and then try with the different functions until it works
If each there are 40 pencils, then divide to find how much each pencil is.
37.20 / 40 = $0.93
Correct answer is D.
After solving, we see that buying the case of 40 pencils is cheaper than buying 40 individual pencils.
Hope This Helped! Good Luck!
