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rewona [7]
4 years ago
6

David gets $35 an hour for cleaning. He gets a 15% raise. He cleans for 60 hours this week. How

Mathematics
1 answer:
11111nata11111 [884]4 years ago
7 0
$35 an hour, 15% raise and 60 hours this week, $35x15/100x60=$315
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Find the value of y when x equals 26 x+4y=54
pishuonlain [190]

Factor out the common term "2".

2(13x+2y) = 54

Now, divide both sides by 2.

13x + 2y = 54/2. <-- <u>We could not divide into a whole number so it's a fraction.</u>

<u />

Simplify 54/2 to 27.

13x + 2y = 27 <--- <u>Since we have a whole number without a letter, we are done with that side.</u>

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Now, we subtract 2y from both sides.

13x = 27 - 2y

Divide both sides by 13.

x = 27 - 2y/13.

<h3>Therefore, we get <u>x = 27 - 2y/13</u></h3>

That would be our final answer.

Good luck on your assignment!

- Emacathy

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the cozy cat shop has 3 calico cats for every gray cat. If they have nine calico cats available, how vany gray cats do they have
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Set up as for portion with X as unknown number of gray cats. So 1/3=x/9. Cross multiply. 3X=9. Divide both sides by 3. X=3.
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What’s the correct answer for this questions?
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B = 6√10

Step-by-step explanation:

In the attached file

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Compare investing ​$2750 at 5​% compounded monthly for 16 years with investing ​$2750 at 6​% compounded monthly for 16 years. Fi
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Hola!! here is a tutor website that can help you answer some questions for any subject:

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3 years ago
The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds,What perc
soldier1979 [14.2K]

Answer:

57.62% of players weigh between 180 and 220 pounds

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 25

What percent of players weigh between 180 and 220 pounds

We have to find the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 180.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{25}

Z = 0.8

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Z = \frac{X - \mu}{\sigma}

Z = \frac{180 - 200}{25}

Z = -0.8

Z = -0.8 has a pvalue of 0.2119

0.7881 - 0.2119 = 0.5762

57.62% of players weigh between 180 and 220 pounds

4 0
3 years ago
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