Factor out the common term "2".
2(13x+2y) = 54
Now, divide both sides by 2.
13x + 2y = 54/2. <-- <u>We could not divide into a whole number so it's a fraction.</u>
<u />
Simplify 54/2 to 27.
13x + 2y = 27 <--- <u>Since we have a whole number without a letter, we are done with that side.</u>
<u />
Now, we subtract 2y from both sides.
13x = 27 - 2y
Divide both sides by 13.
x = 27 - 2y/13.
<h3>Therefore, we get <u>x = 27 - 2y/13</u></h3>
That would be our final answer.
Good luck on your assignment!
- Emacathy
Set up as for portion with X as unknown number of gray cats. So 1/3=x/9. Cross multiply. 3X=9. Divide both sides by 3. X=3.
Answer:
B = 6√10
Step-by-step explanation:
In the attached file
Answer:
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Answer:
57.62% of players weigh between 180 and 220 pounds
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
What percent of players weigh between 180 and 220 pounds
We have to find the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 180.
X = 220
has a pvalue of 0.7881
X = 180
has a pvalue of 0.2119
0.7881 - 0.2119 = 0.5762
57.62% of players weigh between 180 and 220 pounds
