A teacher randomly selects 10 out of her 30 students and finds that the mean height of those 10 students is 5′2". Is this a samp
1 answer:
Answer:
Sample mean
Symbol:
Step-by-step explanation:
Given
Solving (a): Is it sample mean or population mean
From the question, we understand that 10 were selected from a total of 30.
And the mean of the selected 10 is 5'2"
The selected 10 is referred to as sample and the mean of the 10 is the sample mean
Solving (b): Symbol to use.
The symbol for sample mean is:
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Answer: 
Note: to write the domain in interval notation, you'd write [-4,5]
if you need the domain in set-builder notation, then you'd write
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Explanation:
The domain is the set of possible x input values. Look at the left most point (-4,-1). The x coordinate here is x = -4. This is the smallest x value allowed. The largest x value allowed is x = 5 for similar reasons, but on the other side of the graph.
So that's how I got (x is between -4 and 5; inclusive of both endpoints)
Writing [-4,5] for interval notation tells us that we have an interval from -4 to 5 and we include both endpoints. The square brackets mean "include endpoint"
Writing is the set-builder notation way of expressing the domain. The 
portion means "x is a real number"
Note: to write the domain in interval notation, you'd write [-4,5]
if you need the domain in set-builder notation, then you'd write
------------------------------------------------------------------------------
Explanation:
The domain is the set of possible x input values. Look at the left most point (-4,-1). The x coordinate here is x = -4. This is the smallest x value allowed. The largest x value allowed is x = 5 for similar reasons, but on the other side of the graph.
So that's how I got
Writing [-4,5] for interval notation tells us that we have an interval from -4 to 5 and we include both endpoints. The square brackets mean "include endpoint"
Writing
Answer:
219m
Step-by-step explanation:
Since the man observes the car with angle 15 before observing in 33 degrees.
For the first observation
The angle observation gives an angle if 33 degrees with the horizontal.
It gives a triangle which I'll attach to the que,
from the first triangle
Tan 33 = 100/y
Y= 100/ tan 33
Y = 153.99m.
This is the distance from the building to the distance where it was secondly observed( 33).
To find x
tan 15 = 100/(153.99+x)
153.99 + x = 100/ tan 15
153.99 + x = 373.21
The distance between the two observed angles
X= 219m.
