Answer:
Yes it is.
Step-by-step explanation:
C=10 & P=5
3C+4P=50
C+P=15
Solve
3C+4P=50
3C+3P=45
Subtract
P=5
Substitute in equation 2
C+P=15
C+5=15
C=10
I believe that there are 23 different ways to get a total of 20. Then we need to find the number of ways to get each of the 23 different ways. For instance, one way is 6 6 1-1-1-1- 1-1-1-1: 101 / (21-8) = 45 (different ways to get this result) 10 different dice are rolled, giving the 101 in the numerator since the 6 is used twice, divide by 21, since the 1 is used 8 times, divide by 8! Etc., etc., etc. Final answers, add all these results together. I'm not sure about part B! I'm sorry!!!
15 / 20 = 3 × 5 / 4 × 5
simplify 5 from The Denominator and The numerator
= 3 / 4
