Answer:
Step-by-step explanation:
<u>We know that:</u>
- Area of shaded region = Area of square - Area of circles
- Radius of circle = 3 in
- Area of circle = πr²
- Area of square = s²
<u>Solution:</u>
- Area of shaded region = Area of square - Area of circles
- => Area of shaded region = (12²) - 4(22/7 x 3 x 3)
- => Area of shaded region = (144) - 4(22/7 x 9)
- => Area of shaded region = (144) - 4(198/7)
- => Area of shaded region = 144 - 792/7
- => Area of shaded region = 144 x 7/7 - 792/7
- => Area of shaded region = 1008/7 - 792/7
- => Area of shaded region = 1008/7 - 792/7
- => Area of shaded region = 216/7 in²
Answer:
x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)
Step-by-step explanation:
APRB form a cyclic trapezoid
∠APO = x° (Base angle of an isosceles triangle)
∠OPR = ∠ORP (Base angle of an isosceles triangle)
∠ORB = ∠OBR (Base angle of an isosceles triangle)
∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)
Similarly;
∠ORB + ∠ORP + x° = 180°
Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR = ∠ORP we put
We also have;
∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)
Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR
Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.
M=6 is the correct answer
Plz mark brainliest
Answer:
I think that this answer is 22
