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GarryVolchara [31]
3 years ago
15

What is the answer to (x+3)^5

Mathematics
1 answer:
sleet_krkn [62]3 years ago
4 0

(x + 3)⁵

= x⁵ + 3⁵

= x⁵ + 243

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Step-by-step explanation:

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\bf \textit{total cost}\qquad C(r)=\cfrac{28000}{r}-\cfrac{4\pi r^2}{3}+4\pi r^2&#10;\\\\\\&#10;C(r)=\cfrac{28000}{r}-\cfrac{4\pi r^2}{3}+\cfrac{12\pi r^2}{3}\implies C(r)=\cfrac{28000}{r}+\cfrac{8\pi r^2}{3}&#10;\\\\\\&#10;\boxed{C(r)=28000r^{-1}+\cfrac{8\pi }{3}r^2}\\\\&#10;-------------------------------\\\\

\bf \textit{now, let's check the critical points}\\\\&#10;\cfrac{dc}{dr}=-\cfrac{28000}{r^2}+\cfrac{16\pi r}{3}\implies \cfrac{dc}{dr}=\cfrac{16\pi r^3-84000}{3r^2}&#10;\\\\\\&#10;0=\cfrac{16\pi r^3-84000}{3r^2}\implies 84000=16\pi r^3\implies 5250=\pi r^3&#10;\\\\\\&#10;\boxed{\sqrt[3]{\cfrac{5250}{\pi }}=r}

now, I'd like to point out, we also get critical points from the denominator being zero, so 3r²=0, gives us r=0, which is a critical point, however, with a radius of 0, well, there's no volume, so, the is not feasible for the phenomena, so is not applicable, though is a valid critical point

critical points from the denominator being zero, are usually asymptotic or "cusps", the function reaches an extrema, however the tangent is not horizontal and thus is not differentiable at that point, even though is an extrema.

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4 years ago
What is the approximate distance between the points (-5,1) and (-2,3) on a coordinate grid? Show me an example please
yaroslaw [1]

Answer:

d=\sqrt{13}\ units   or  d=3.61\ units

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

A(-5,1)\\E(-2,3)  

substitute the values

d=\sqrt{(3-1)^{2}+(-2+5)^{2}}

d=\sqrt{(2)^{2}+(3)^{2}}

d=\sqrt{13}\ units

d=3.61\ units

the graph in the attached figure  

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3 years ago
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