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____ [38]
2 years ago
12

Mark ran 875 miles in the track club this year . Mark ran in 52 track meets and ran the same number of miles in each . how many

miles did Mark run in each track meet write answer in a mixed number ​
Mathematics
1 answer:
dmitriy555 [2]2 years ago
8 0

Answer:

16\frac{43}{52}

Step-by-step explanation:

875/52 = 16\frac{43}{52}

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A doctor estimates that a particular patient is losing bone density at a rate of 3% annually. The patient currently has a bone d
kompoz [17]

Answer:

The function f(x) is represented by:

f(x)=1500(0.97)^x

Hence, a=1500 and b=0.97

Step-by-step explanation:

The patient currently has a bone density of 1,500 kg/mg^3.

A doctor estimates that a particular patient is losing bone density at a rate of 3% annually.

This means that the bone density that is remaining is:

100-3=97%

which is also represented as: 97%=97/100=0.97

Hence, the function f(x) that represents the bone density after x years is represented by:

f(x)=a(0.97)^x

where a is the initial bone density which is given to be: 1500 kg/mg^3.

Hence, the function is:

f(x)=1500(0.97)^x

6 0
3 years ago
Read 2 more answers
CAN SOMEONE HELP ME!!!!!!!!!!!!!!!
Crazy boy [7]

Answer: 150 min

Step-by-step explanation:

2 hours = 120 min, 120 + 30 min = 150 min

3 0
3 years ago
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Can some one help me im confused
LekaFEV [45]
1) first one....90-27=63°
2)180-128=52°>>>>that is B
3)first one is suppliment....so A
4)180-125=55°....I think D....but not in pic !!!

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4 0
3 years ago
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Two boxes of tea weight 3 oz. The Tea Time Tasty Tea Company packs 112 boxes in a case of tea. How many pounds does each case of
Marysya12 [62]
Your answer 336 because you multiply 112 x 3
6 0
3 years ago
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Fifteen SmartCars were randomly selected and the highway mileage of each was noted The analysis yielded a mean of 47 miles per g
laiz [17]

Answer: a. 47 plusminus (1.753*(5 ÷ 3.8730)

Step-by-step explanation:

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation = 5

n = number of samples = 15

z represents the test statistic

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the test statistic score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 15 - 1 = 14

Since confidence level = 90% = 0.90, α = 1 - CL = 1 – 0.90 = 0.1

α/2 = 0.1/2 = 0.05

the area to the right of z0.05 is 0.05 and the area to the left of z0.05 is 1 - 0.05 = 0.95

Looking at the t distribution table,

z = 1.753

Margin of error = 1.753(5 ÷ 3.8730)

Confidence interval = 47 ± 1.753(5 ÷ 3.8730)

8 0
3 years ago
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