F(x) = -3(x - 11)(x + 1)

Mathematics

1 answer:

il63 [147K]3 years ago

8 0

Answer:

Step-by-step explanation:

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Help me do examples for a function and a non function

bekas [8.4K]

Answer:

{(1,2) (3,4) (5,6)} and {(1,2) (1,4) (5,6)}

Step-by-step explanation:

you really want to think of a function as a vending machine. if you press B12 on a vending machine because thats where the chips are, only the chips should come out. in a function, the input value aka x (B12, what youre putting in) should only have one output value aka y, (the chips)

an example of a function would be {(1,2) (3,4) (5,6)}

an important thing to remember is that one output value can belong to multiple input values. there can be chips (output) in both B12 and C12 (inputs) BUT as i said before, there CANNOT be two outputs for one input. B12 cannot give you both chips and a drink.

using this, another example of a function would be {(1,2) (3,2) (5,2)}

an example of an non function would be {(1,2) (1,4) (5,6)} because x, the input value, has multiple output values which is not possible. the output of 1 can not be 2 and 4 at the same time which we can see in the (x,y) coordinates.

4 0

3 years ago

These ordered pairs, {(2,4) (3,6) (4,8) (5,10)}, are a function. True False

ki77a [65]

Answer:

True

Step-by-step explanation:

In order for a relation (a set of ordered pairs) to be considered a function, every value in the domain (the set of all the first numbers in the pair) is associated with one value in the range (the set of all second numbers in the pair). This is easiest to see visually. Our domain is the set {2, 3, 4, 5} and our range is the set {4, 6, 8, 10}, and we can visualize the ordered pair (2, 4) as an "arrow" starting a 2 in the domain and ending at 4 in the range. When seen this way, a relation is a function if every value in the domain only has one arrow coming out of it. We can see from the attached picture that the ordered pairs in the problem are a function, so this statement is true.