F(x) = -3(x - 11)(x + 1)

Mathematics

1 answer:

il63 [147K]3 years ago

8 0

Answer:

Step-by-step explanation:

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Suppose that the functions g and f are defined as follows.

Sholpan [36]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Given:

$\to g(x)= -3+2x^2 \\\\\to f(x)=9-6x$

Calculating the value of $(\frac{g}{f})(2)$ :

$\to (\frac{g}{f}) (2)= (\frac{g(x)}{f(x)}) \times (2)$

$=\frac{2x^2-3}{9-6x} \times 2\\\\=\frac{2\cdot 2^2-3}{3(3-2\cdot 2)} \\\\=\frac{2\cdot 4-3}{3(-1)}\\\\ =\frac{8-3}{-3}\\\\ =\frac{5}{-3}\\\\ = - \frac{5}{3}\\\\$

x= $- \frac{\sqrt{3}}{2}$ and x= $\frac{\sqrt{3}}{2}$ are not in the domain.

Domain: $x \belong (- \infty, -\frac{\sqrt{3}}{2})\cup (- \frac{\sqrt{3}}{2}, \frac{\sqrt{3}}{2} )\cup (\frac{\sqrt{3}}{2}, \infty)$

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3 years ago

Evaluate 9 times p when p= 3.5

zysi [14]

Answer: 31.5

Step-by-step explanation:

9*3.5=31.5

Hopefully this is what they meant

7 0

3 years ago

Graph the following state and show the a h and k values. <br> y=2(x+3)^2-4

Arte-miy333 [17]

This equation is in vertex form. Vertex form is y=a(x-h)^2+k, where (h,k) is the vertex. In this equation, h= -3, and k= -4. So, the vertex would be at (-3,-4). A tells us if the parabola will be positive or negative. In this case, it is positive, so the parabola opens upward. Then, you can solve for x-intercept by letting y=0 and solving for x. Then, you can find the y-intercept by setting x=0 and solving for y. Finally, graph the parabola.