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elena55 [62]
3 years ago
6

PLEASE HELP ASAP!!

Mathematics
1 answer:
spayn [35]3 years ago
6 0
Huygens
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Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. q2+11q
Sedbober [7]

Answer:

(q+\frac{11}{2})^2-\frac{121}{4}

Step-by-step explanation:

We have been given an expression q^2+11q. We are asked to complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

We know that a perfect square trinomial is in form a^2+2ab+b^2.

To convert our given expression into perfect square trinomial, we need to add and subtract (\frac{b}{2})^2 from our given expression.

We can see that value of b is 11, so we need to add and subtract (\frac{11}{2})^2 to our expression as:

q^2+11q+(\frac{11}{2})^2-(\frac{11}{2})^2

Upon comparing our expression with (a+b)^2=a^2+2ab+b^2, we can see that a=q, 2ab=11q and b=\frac{11}{2}.

Upon simplifying our expression, we will get:

(q+\frac{11}{2})^2-\frac{11^2}{2^2}

(q+\frac{11}{2})^2-\frac{121}{4}

Therefore, our perfect square would be (q+\frac{11}{2})^2-\frac{121}{4}.

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it 28 by adding 6 +1 is 7 and times it by 4

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