Answer:
(3p^3-21p^2=26p=24/p)-5
Step-by-step explanation:
Answer:
24 years
Step-by-step explanation:
Total = start*(1 + interest rate / amount of times compounded per month)^(years*amount of compounds per year)
6000 = 3000*(1+0.03/4)^(4x)
6000 = 3000* ((403/400)^4)^x
2 = ((403/400)^4)^x
x = log base-((403/400)^4) of 2 = x
x = 23.19
rounding down 23 years (but you probably want a year over that to get at least 6000, so 24)
Answer: 21
Step-by-step explanation:
9x7=63
63/3=21
Answer:
y = 400(1.01)^t
Step-by-step explanation:
Firstly find the rate
(Take any balance for two years, e. g 400 and 404,412.12 and 416.24,etc to get simple interest)
408.04-404= 4.04
I=(P*R*T)/100
From which R=(100*I)/PT
R= 100*4.04/404*1
R=1%
Using compound interest formula
A =P(1+r/100)^n
where n is time
substituting each value
y = 400(1+1/100)^t
y= 400(1.01)^t
well the x would be 2 and the y would be 25 i think
