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Scilla [17]
3 years ago
12

Decrease £140 by 22%

Mathematics
1 answer:
Kobotan [32]3 years ago
5 0

Answer:

109.2

Step-by-step explanation:

math

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PLEASE HELP IM DESPERATE precalculus. also 50 points!! please god help
kompoz [17]

Answer:

For B thru F these options will vary but here how you do it

B. Step 1 Draw the 4 Quadrants.

Then Draw the Triangle in the lower right quadrant which we call quadrant 4. Label the X axis as Adjacent and positive. Label the Y axis as Opposite and negative. Label the Slanted side as the hypotune and AS POSITVE SINCE HYPOTENUSE IS ALWAYS POSITIVE.

FOR C. IN QUADRANT 2, PLOT A POINT AT 0,12 AND AT (-5,0). CONNECT THE DOTS AND IT FORMS A TRIANGLE. Label the X axis as adjacent and negative and the y axis as positve and opposite and label the slanted side hypotunese and positive.

FOR D Draw a straight line along the x axis then draw a slanted line passing through (5,-1). In between them put the theta symbol in there.

The labeling is the same for C.

For E. Since tan must be positve and secant must be positve, our triangle must be in the 1st Quadrant. Draw any right triangle as long it is in the first quadrant

The x axis is adjacent and positve. The y axis is opposite and positve. The hypotenuse is the slanted side and it is positve.

For F. Since sin is negative and cos is positve the triangle is in the 4th quadrant. Draw any triangle in the 4th quadrant and the labeling is the same for Problem B.

2. We can find the sec of cos by flipping cosine.

\cos( \frac{x}{y} )  =  \sec( \frac{y}{x} )

\cos( \frac{1}{2} )  =  \sec(2 )

Sec is 2.

To find the cotangent, first let find the sin then tan.

We can use the identity

\cos( {theta}^{2} )  +  \sin( {theta}^{2} )  = 1

Let plug in the number

\cos( \frac{ {1}^{2} }{{2}^{2} } )  +  \sin(x {}^{2} )  = 1

\cos( \frac{1}{4} )  +  \sin(x {}^{2} )  = 1

\sin(x {}^{2} )  =   1 -  \frac{1}{4}

\sin(x {}^{2} )  =  \frac{3}{4}

\sin(x)  =  \frac{ \sqrt{3} }{ \sqrt{4} }

\sin(x)  =  \frac{ \sqrt{3} }{2}

Since sin is negative, sin x=

-  \frac{ \sqrt{3} }{2}

Now let apply the formula

\frac{ \sin(x) }{ \cos(x) }  =  \tan(x)

\frac{ \frac{ -  \sqrt{3} }{2} }{ \frac{1}{2} }  =  \tan(x)

-  \sqrt{3}

Now let find cotangent we can the reciprocal of

tan.

\tan=  -  \sqrt{3}

\cot =   - \frac{1}{ \sqrt{3} }

Rationalize denominator

\frac{ - 1}{ \sqrt{3} }  \times   \frac{ \sqrt{3} }{ \sqrt{3} }  =  \frac{ \sqrt -{ 3} }{3}

cotangent equal

-  \frac{ \sqrt{ 3} }{3}

4 0
3 years ago
Cassie made 9 identical sundaes using 4 pints of ice cream. How much ice cream did Cassie use for each sundae?
Dvinal [7]

Answer:

20.50

Step-by-step explanation:

<u>9/4</u> as a decimal is <u>2.25</u>. an you need to find the ice cream Cassie used the way Would say is multiply <u>2.25</u> by 9 and you get <u>20.5</u>. I hope this helps

3 0
3 years ago
Two​ researchers, Jaime and​ Mariya, are each constructing confidence intervals for the proportion of a population who is​ left-
egoroff_w [7]

Complete question :

Two researchers, Jaime and Mariya, are each constructing confidence intervals for the proportion of a population who is left-handed. They find the point estimate is 0.13. Each independently constructed a confidence interval based on the point estimate, but Jaime’s interval has a lower bound of 0.097 and an upper bound of 0.163, while Mariya’s interval has a lower bound of 0.117 and an upper bound of 0.173. Which interval is wrong? Why?

Answer:

Mariya's interval

Step-by-step explanation:

Point estimate = 0.13

Mariya's confidence interval :

Lower boundary = 0.117

Upper boundary = 0.173

Jamie's confidence interval :

Lower boundary = 0.097

Upper boundary = 0.163

The correct confidence interval should have an average value equal to the value of the point estimate ;

Jamie's confidence interval average :

(0.097 + 0.163) / 2 = 0.26 / 2 = 0.13

Mariya's confidence interval average :

(0.117 + 0.173) / 2 = 0.29 / 2 = 0.145

Based on the confidence interval average obtained we can conclude that Mariya's interval is wrong as it the average obtained is greater than the point estimate.

0.145 > 0.13

3 0
3 years ago
Point B is the image of point A when point A is rotated about the origin. What is known about point A and B?
Oksanka [162]

Answer:

change time in words 3:45

6 0
3 years ago
Michael is 4 times as old as Brandon and is also 27 years older than Brandon.
gtnhenbr [62]
M=4b
m=27+b

subsitute
4b=27+b
minus b
3b=27
divide 3
b=9
sub back
4b=m
4(9)=m
36=m

michel=36 and brandon is 9
3 0
4 years ago
Read 2 more answers
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