Question:
A fly is standing on a boulder which is rolling down a hill. The forward torque the fly exerts on the boulder when it has rolled 'x' meters, in Newton meters is given by
![\tau(x) = \dfrac{2}{1,000} \cdot sin \left(\dfrac{2 \cdot \pi \cdot (x + 0.2)}{4} \right )](https://tex.z-dn.net/?f=%5Ctau%28x%29%20%3D%20%5Cdfrac%7B2%7D%7B1%2C000%7D%20%5Ccdot%20sin%20%5Cleft%28%5Cdfrac%7B2%20%5Ccdot%20%5Cpi%20%5Ccdot%20%28x%20%2B%200.2%29%7D%7B4%7D%20%5Cright%20%29)
Answer:
y = 0
Step-by-step explanation:
The general form of the sine function is presented as follows;
y = A·sin[B·(x - C)] + D
Where;
A = The amplitude
C = The horizontal shift
D = The vertical shift above the generic midline of y = 0 = Constant
By comparison with the general equation for torque, we have that the constant D = 0, therefore, the vertical shift = 0, and the midline of the the given function = The midline of the generic sine function which is y = 0.
A translation is a transformation in which every point moves the same distance in the same direction
Given:
The expression is:
![6x^2+3x+21](https://tex.z-dn.net/?f=6x%5E2%2B3x%2B21)
To find:
The factor of the given expression by GCF.
Solution:
We have,
![6x^2+3x+21](https://tex.z-dn.net/?f=6x%5E2%2B3x%2B21)
Here, 3 is the greatest common factor (GCF) of
.
Taking out GCF, we get
![6x^2+3x+21=3(2x^2+x+7)](https://tex.z-dn.net/?f=6x%5E2%2B3x%2B21%3D3%282x%5E2%2Bx%2B7%29)
Therefore, the required factor form of the given expression is
.
Answer:
same way here too lol ok so nvm about the points but can i pls just have brainliest
342.0
340.8 plz i just need one brainlyest