Answer:
The sphere has a diameter of 32 in.
Step-by-step explanation:
The length of the radius is one-half the length of the diameter, definitely, and its diameter is the maximum distance from two counter-pointers on the surface of the sphere and its length is twice as high as that of the radius, because the radius is the distance from the centre of the sphere to any point of the border of the sphere.
The volume (V), where r is a transmitter, may be measured. In this case, the volume will be equal to the volume of the sphere.
Hope this helps.
Answer:
Step-by-step explanation:
sample size = n = 60
Sample mean = x bar = 5.25
Sample sd = s = 0.55
Std error of sample = s/sqrt n = 0.071
(One tailed test)
Mean difference = 5.25-5.4 = -0.15
Test statistic t = Mean diff/Se = -2.11
df=59
(since population std dev is not known t test is used)
p value =0.01955
Since p <alpha =0.05 we reject null hypothesis.
The results suggest about the sample group that the sample is from a population with a mean less than 5.4
The answer is: "10 cm" .
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Method 1)
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2L + 2w = 40 ; Since the formula for perimeter of a rectangle (Note: a square is a rectangle) is:
P = 2L + 2w ; Note: L = length; w = width; P = perimeter;
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Factor out a "2":
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" 2L + 2w = 40" ;
2 (L+ w) = 40;
Divide each side of the question by "2" ;
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[2 (L + w)] / 2 = 40 / 2 ;
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to get: (L + w) = 20 ;
Note: this "rectangle is a square" ; so L= w".
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20 /2 = 10 ;
L + w = 10 + 10 = 20.
This is a square, so each side of the square is the same length.
Each side is: 10 cm .
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Method 2)
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We are given: The perimeter (sum of the lengths of all sides) of a square is "40 cm." Since a square has 4 sides of equal length:
Each side is: 40 cm / 4 = 10 cm.
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