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Rudiy27
3 years ago
14

Margie received her store order on 12/3/16 at 4AM. She just opened one of the

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

Exp Date: 1/17/2017

Exp Time: 4:00am

Prep Date: 12/3/2016

Prep Time: 4:00am

Initials: 12/7/2016

Step-by-step explanation:

A well-detailed version of the question has been uploaded in form of an image for easier understand.

Looking at the question, it was said that she received her store order on 12/3/2016 at 4am, this implies that the prep date and time are 12/3/2016 and 4am respectively. Also, it was said that the expiration date was printed on the product and it is 1/17/2017. Obviously, the expiration time would also be 4am because it was prepared at 4am and if we calculate in. 24hours we would get 4am at the expiration date as well. Lastly, we were told she opened the product she received on 12/7/2016 which is the initial date the product was used. From all these we can deduce the following:

Exp Date: 1/17/2017

Exp Time: 4:00am

Prep Date: 12/3/2016

Prep Time: 4:00am

Initials: 12/7/2016

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Answer:

9x + 5y = 29 ........... (1) and

3x + y = 7 ........... (2)

Each game of ping pong requires 1 number of token and each game of pinball requires 4 number of tokens.

Step-by-step explanation:

Let, each game of ping pong requires x number of tokens and each game of pinball requires y number of tokens.

So, from the given conditions we can write

9x + 5y = 29 ........... (1) and

3x + y = 7 ........... (2)

Now, solving equations (1) and (2) we get,

9x + 5(7 - 3x) = 29

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⇒ y = 4 tokens.

So, each game of ping pong requires 1 number of token and each game of pinball requires 4 number of tokens. (Answer)

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

(3⁴ × 5⁴)⁻²

Simplify the terms inside the parentheses. 3⁴ × 5⁴ is the same as 15⁴ because even though the base numbers are different, the exponents are the same which makes it similar.

(15⁴)⁻²

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Since we can not have a negative exponent, we are going to change this into a fraction. We do this by putting this term in a fraction where 1 is the numerator and the term is the denominator.

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