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MA_775_DIABLO [31]

3 years ago

8

Mr. Tan bought a mobile phone at a discount of 25 %. The original price of mobile phone was of $400. How much did he pay for the

mobile phone.?

1 answer:

snow_lady [41]3 years ago

5 0

Answer:

$300

Step-by-step explanation:

$400 is 100% of the price

25% is a quarter of 100%

A quarter of 400 is 100 so the discount was $100

400-100 =300

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Someone help ASAP!!!!!!

Alchen [17]

Answer:

Length, l = 11 ft.

Width, w = 9 ft.

Step-by-step explanation:

From the given data, the area of the rectangle = 99 ft².

Area of the rectangle = Length, l X Width, w

Here, Length, l = 7 more than twice the width

⇒ Length, l = 7 + 2w

Therefore, Area, A = 99 = (7 + 2w)w

⇒ 99 = 7w + 2w²

⇒ 2w² + 7w - 99 = 0

Solve the Quadratic equation using the formula: x = $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ for the quadratic equation ax² + bx + c = 0.

Therefore, w = $\frac{-7 \pm \sqrt{7^2 -4(2)(-99)}}{2(2)}$

$= \frac{-7 \pm \sqrt{49 + 8(99)}}{4}$

$= \frac{-7 \pm + \sqrt{841}}{4}$

Since, $\sqrt{841} = 29$ we get:

$w = \frac{-7 \pm 29}{4}$

This gives two values of 'w', viz., w = $\frac{-7 - 29}{4}$ , $\frac{-7 + 29}{4}$

$\implies w = \frac{22}{4}, \frac{-36}{4}$

⇒ w = $\frac{22}{4}$ , -9.

We take the integer values.

If w = -9, then l = 2(-9) + 7

⇒ l = - 18 + 7 = - 11

Therefore, the length, l of the rectangle = - 11 ft.

and the width, w of the rectangle = - 9 ft.

Hence, the answer.

3 0

2 years ago

A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0

2 years ago

A $3000 loan has an annual interest rate of 6.6% on the amount borrowed. How much time has elapsed if the interest is now $1386?

san4es73 [151]

Answer:

7

Step-by-step explanation:

time=<u>interest</u>

P*R

time=<u>1386*</u>100

6.6 * 3000

<u>time=7</u>

7 0

2 years ago

Three eighths of the 32 children in the club were girls. <br> How many boys were in the club?

vivado [14]

Answer:

20

Step-by-step explanation:

3/8* 32= 12

32-12=20

12 Girls

20 Boys

8 0

2 years ago

Read 2 more answers

Compute Δy and dy for the given values of x and dx = Δx. (Round your answers to three decimal places.) y = ex, x = 0, Δx = 0.4

kobusy [5.1K]

Answer:

0.492

Step-by-step explanation:

According to the given situation, the calculation of Δy and dy is shown below:-

$y = e^x, x = o, \Delta x = 0.6$

$dy = f'(x) = e^x$

$dy = e^x dx$

$= e^x (0.4)$

$dy = 0.4e^x$

$\Delta y = f(0.4) - f(0)$

$= e^{0.4} - e^0$

Now we use the scientific calculator or spreadsheet to determine the exponential value

= 1.491824698 - 1

= 0.491824698

or

= 0.492

Therefore for computing the Δy and dy we simply applied the above formula.

Hence, the answer is 0.4918

5 0

3 years ago