Ok now that i understand the question better i say it is D
It’s b since 3% times 250 equals 7.4 and 7.4 times 14 equals 105 so you add 105 to 250 and you get 355
1. 22 - 3x + 7x = 4(x + 5)
22 - 3x + 7x = 4x + 20
<u> +3x +3x +3x </u>
22 + 10x = 7x + 20
<u> -7x -7x </u>
22 + 3x = 20
<u>-22 -22</u>
<u>3x</u> = -<u>2</u>
3 3
x = -2/3
2. 6(2x - 3) = 3(3 - 5)
12x - 18 = 3(-2)
12x - 18 = -6
<u> +18 +18</u>
<u>12x</u> = <u>12</u>
12 12
x = 1
3. 6x - 14 = 2(3x - 7)
6x - 14 = -3x
6x - 14 = 2(-7)
6x - 14 = -14
<u> +14 +14</u>
<u>6x</u> = <u>0</u>
6 6
x = 0
4. 6x + 3(x - 4) = 8(x - 3)
6x + 3x - 12 = 8x - 24
9x - 12 = 8x - 24
<u>-8x -8x </u>
x - 12 = -24
<u> +12 +12</u>
x = -12
Answer:
<em>A.) There is a 3.4% chance that a random sample of 50 expectant mothers will have a mean age of 26.5 years old or greater if the mean age for a first time mother is 26 years old.</em>
Step-by-step explanation:
The mean age for a first time mother is assumed 26 years old (null hypothesis) and <em>p-value</em> of the sample mean (26.5 years ) is found as 0.034.
This is the probability of having first time mother mean age 26.5 or greater <em>under the assumption of null hypothesis. </em>
