Question

Use the converse of the pythagorean theorem to determine whether the triangle with the given vertices is a right triangle. (2, 1)(6, 4), (–4, 9)

Answer 1

Hello : 
let : A(2, 1) , B(6, 4) , C(–4, 9)
calculate : AB  , AC,  BC 
AB = √((6-2)² + (4-1)²) = √25 = 5
AC= √((-4-2)² + (9-1)²) = √100 = 10
BC= √((-4-6)² + (9-4)²) = √125 
by  pythagorean theorem : BC² = AC² + AB² 
the triangle is rectangle in : A