Answer:
dfn
Step-by-step explanation:
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
you did not specify the diamiter of the can please add another question and i will help
Step-by-step explanation:
it is imposible to answer right now
Answer:
<em>y = -2x + 25/2</em>
Step-by-step explanation:
Slope intercept form is y = mx + b.
You must solve the equation for y.
4x + 2y = 25
Subtract 4x from both sides.
2y = -4x + 25
y = -2x + 25/2
The last graph represents a system with no solutions. The solution to a system of equations is the point at which both lines intersect. Because the equations in the last graph don't intersect and are parallel, it has no solutions. Hope this helps :))
