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UkoKoshka [18]
3 years ago
10

500 million houses in 42 hours how many per minute

Mathematics
1 answer:
Zigmanuir [339]3 years ago
3 0

Answer:

I think one hundred twenty-five million

Step-by-step explanation:

500 million divided by 4

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If the pressure is 6 pounds per inch when the temperature is 440 F, find the pressure exerted when the temperature of the gas is
SVEN [57.7K]

4.18

(380*6)/440=4.18

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3 years ago
PLS SOMEONE HELP QUICK
alexdok [17]

Answer:

THE PICTURE IS TO SMALL

Step-by-step explanation:

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In 2015, the population of a small town in Florida is 95. If he population increases 15% every year, approximately what will the
vova2212 [387]

The population is increasing every year. so we use exponential growth function

y=a(1+r)^x

Where 'a' is the initial population

r is the rate of increase

x is the years

y is the final population

In 2015, the population of a small town in Florida is 95

Initial population a= 95

r= 15%= 0.15

x = 2023 - 2015 = 8 years

Plug in all the values and find out y

y=a(1+r)^x

y=95(1+0.15)^8

y = 290.607

The population in 2023 is 291

8 0
3 years ago
Which equation represents the line with a slope of 5/6 that passes through the point (-2, 1)?
andreyandreev [35.5K]

Answer:

Step-by-step explanation:

Slope m = 5/6

The points (-2,1)

So; y1 = 1 and x1 = -2

The equation is y - y1 = m(x - x1)

y - 1 = 5/6(x + 2)

Multiply each term by 6

6y - 6 = 5(x + 2)

6y - 6 = 5x + 10

6y = 5x + 10 + 6

6y = 5x + 16

- 5x + 6y = 16

Multiplying by minus

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5 0
3 years ago
Read 2 more answers
Integrate the following
enot [183]

I suppose you mean to have the entire numerator under the square root?

\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx

We can use a trigonometric substitution to start:

x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt

Then for x=2, t=\sec^{-1}1=0; for x=4, t=\sec^{-1}2=\frac\pi3. So the integral is equivalent to

\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt

We can write

\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t

so the integral becomes

\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}

7 0
3 years ago
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