Ax^2+bx+c=0
a=2
b=-1
c=-3
b+-sqrt( b^2 - 4ac)
2a
so...
-1 +- sqrt(1 + 24)
4
-1 +- 5
4
x= -1 + 5 = 1
4
or
x= -1 - 5 = -3/2
4
1) last number times 4 and subtract 1
2) last number times2 and add 2
3) you figure out
The point P(–4, 4) that is of the way from A to B on the directed line segment AB.
Solution:
The points of the line segment are A(–8, –2) and B(6, 19).
P is the point that bisect the line segment in .
So, m = 2 and n = 5.
By section formula:
P(x, y) = (–4, 4)
Hence the point P(–4, 4) that is of the way from A to B on the directed line segment AB.
Could you post the equation? I’d be happy to help!
I believe it’s b...
This is obviously because the slope does depend on the chosen points in a graph