Add -9 and -7 using 2nd compliment

The hardware that takes the input data and works with it

pogonyaev

Answer:

Examples of input devices include keyboards, mice, scanners, digital cameras and joysticks.

Explanation:

5 0

3 years ago

Write a program with the total change amount as an integer input, and output the change using the fewest coins, one coin type pe

riadik2000 [5.3K]

Answer:

In Python:

cents = int(input("Cents: "))

dollars = int(cents/100)

quarters = int((cents - 100*dollars)/25)

dimes = int((cents - 100*dollars- 25*quarters)/10)

nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)

pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels

if not(dollars == 0):

if dollars > 1:

print(str(dollars)+" dollars")

else:

print(str(dollars)+" dollar")

if not(quarters == 0):

if quarters > 1:

print(str(quarters)+" quarters")

else:

print(str(quarters)+" quarter")

if not(dimes == 0):

if dimes > 1:

print(str(dimes)+" dimes")

else:

print(str(dimes)+" dime")

if not(nickels == 0):

if nickels > 1:

print(str(nickels)+" nickels")

else:

print(str(nickels)+" nickel")

if not(pennies == 0):

if pennies > 1:

print(str(pennies)+" pennies")

else:

print(str(pennies)+" penny")

Explanation:

A prompt to input amount in cents

cents = int(input("Cents: "))

Convert cents to dollars

dollars = int(cents/100)

Convert the remaining cents to quarters

quarters = int((cents - 100*dollars)/25)

Convert the remaining cents to dimes

dimes = int((cents - 100*dollars- 25*quarters)/10)

Convert the remaining cents to nickels

nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)

Convert the remaining cents to pennies

pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels

This checks if dollars is not 0

if not(dollars == 0):

If greater than 1, it prints dollars (plural)

if dollars > 1:

print(str(dollars)+" dollars")

Otherwise, prints dollar (singular)

else:

print(str(dollars)+" dollar")

This checks if quarters is not 0

if not(quarters == 0):

If greater than 1, it prints quarters (plural)

if quarters > 1:

print(str(quarters)+" quarters")

Otherwise, prints quarter (singular)

else:

print(str(quarters)+" quarter")

This checks if dimes is not 0

if not(dimes == 0):

If greater than 1, it prints dimes (plural)

if dimes > 1:

print(str(dimes)+" dimes")

Otherwise, prints dime (singular)

else:

print(str(dimes)+" dime")

This checks if nickels is not 0

if not(nickels == 0):

If greater than 1, it prints nickels (plural)

if nickels > 1:

print(str(nickels)+" nickels")

Otherwise, prints nickel (singular)

else:

print(str(nickels)+" nickel")

This checks if pennies is not 0

if not(pennies == 0):

If greater than 1, it prints pennies (plural)

if pennies > 1:

print(str(pennies)+" pennies")

Otherwise, prints penny (singular)

else:

print(str(pennies)+" penny")

4 0

3 years ago

Write a function that implements another stack function, peek. Peek returns the value of the first element on the stack without

devlian [24]

Answer:

See explaination

Explanation:

StackExample.java

public class StackExample<T> {

private final static int DEFAULT_CAPACITY = 100;

private int top;

private T[] stack = (T[])(new Object[DEFAULT_CAPACITY]);

/**

* Returns a reference to the element at the top of this stack.

* The element is not removed from the stack.

* atreturn element on top of stack

* atthrows EmptyCollectionException if stack is empty

*/

public T peek() throws EmptyCollectionException

{

if (isEmpty())

throw new EmptyCollectionException("stack");

return stack[top-1];

}

/**

* Returns true if this stack is empty and false otherwise.

* atreturn true if this stack is empty

*/

public boolean isEmpty()

{

return top < 0;

}

//please replace "at" with the at symbol

Note:

peek() method will always pick the first element from stack. While calling peek() method when stack is empty then it will throw stack underflow error. Since peek() method will always look for first element ffrom stack there is no chance for overflow of stack. So overflow error checking is not required. In above program we handled underflow error in peek() method by checking whether stack is an empty or not.

3 0

4 years ago

The qwerty keyboard is the most common layout of keys on a keyboard.

vagabundo [1.1K]

The qwerty keyboard is the most common keyboard.

6 0

4 years ago

Read 2 more answers

Can you guess why some of the nodes would still have statically assigned ip addresses?

LiRa [457]

The manual assignment of an IP address to a system is called static addressing. Since the assignment of IP has been entered manually using ARP utility, the network administrators probably forgot to remove the manually configured nodes with IP addresses.

7 0

3 years ago