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Jobisdone [24]
3 years ago
11

A straight line L is perpendicular to line 3x-2y+4=0. The area of triangle formed by the line L and coordinate axes is 27 sq.uni

t find equation of line L​
Mathematics
2 answers:
Scorpion4ik [409]3 years ago
6 0

Step-by-step explanation:

y=mx+c

3x-2y+4=0

-2y=-3x+4(divide all sides by -2)

<h2> =y=3/2x-2</h2>
tatiyna3 years ago
6 0
First write the equation in the standard form of y=mx+c
3x-2y+4=0
3x+4=2y
( divide by 2)
3/2x+2=y
Now let’s find the perpendicular line to y=3/2x+2
You just have to get the opposite of the slope 3/2 which is -2/3
If you multiply 3/2 by -2/3 you will get -1 this proofs it really is the perpendicular slope your are looking for
Hence
The equation of line L is
y=-2/3+2
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Snowfall will accumulate 0.02 m every hour.
4 0
3 years ago
The square of two times an interger is 6 more than ten times the integer. Find the integer
MArishka [77]
So for this problem, you will need to write out the equation before you can solve the question. The square of two times an integer translates into 2x². In a word problem, "is" means =. Therefore, 2x² is equal to the other half of the equation. To write out the other half of the equation, you have to know that "is more than" means addition. So, 10x+6 is the other half of the equation. your final equation becomes 2x²=10x+6. Then solve the equation like in any other problem: 2x²=10x+6 becomes 2x²-10x-6=0, and then factor or use the quadratic formula.
3 0
3 years ago
Need help
amm1812

Answer:

b

Step-by-step explanation:

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7 0
3 years ago
Find a square root that lies between 17 and 18.
olga nikolaevna [1]
Easy
if x is the number
sqrt x is between 17 and 18

17<√x<18
squaer the whole thing
289<x<324
x could be 300
it could be sqrt of 300
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5 0
3 years ago
Express the confidence interval 0.333less thanpless than0.555 in the form ModifyingAbove p with caret plus or minus Upper E. Mod
elena-14-01-66 [18.8K]

Answer:

The confidence interval is (0.444 ± 0.111).

Step-by-step explanation:

The general form of a confidence interval for single proportion is: (\hat p- E

The interval provided is: (0.333 < p < 0.555)

Then

\hat p-E=0.333...(i)\\\hat p + E = 0.555...(ii)

Solving the two equation simultaneously:

Add (i) and (ii),

2\hat p=0.888\\\hat p=\frac{0.888}{2}\\ =0.444

Substitute the value of \hat p in (i) to compute the value of <em>E:</em>

\hat p-E=0.333\\0.444-E=0.333\\E=0.444-0.333\\=0.111

Thus, the confidence interval is,

(0.444-0.111

7 0
3 years ago
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