First write the equation in the standard form of y=mx+c 3x-2y+4=0 3x+4=2y ( divide by 2) 3/2x+2=y Now let’s find the perpendicular line to y=3/2x+2 You just have to get the opposite of the slope 3/2 which is -2/3 If you multiply 3/2 by -2/3 you will get -1 this proofs it really is the perpendicular slope your are looking for Hence The equation of line L is y=-2/3+2
