Question

Write root 3 x root 6 in the form b root 2 where b is an integer​

Answer 1

Answer:

$\sqrt{3}\cdot\sqrt{6}=3\cdot\sqrt{2}$

Step-by-step explanation:

Radicals

We have the expression:

$\sqrt{3}\cdot\sqrt{6}$

Since 6=2*3, it can be rewritten as:

$\sqrt{3}\cdot\sqrt{6}=\sqrt{3}\cdot\sqrt{2}\cdot\sqrt{3}$

Joining like radicals:

$\sqrt{3}\cdot\sqrt{6}=\sqrt{3}\cdot\sqrt{3}\cdot\sqrt{2}$

$\sqrt{3}\cdot\sqrt{6}=\sqrt{9}\cdot\sqrt{2}$

$\boxed{\sqrt{3}\cdot\sqrt{6}=3\cdot\sqrt{2}}$

This is the required form with b=2