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blsea [12.9K]
3 years ago
13

An expression is shown below. What is the value of the expression?

Mathematics
1 answer:
dsp733 years ago
6 0

Answer:

Step-by-step explanation:

First you need to set up the equation 2/3+1/4/1/2, and we know that there is a stratgey for dividing fractions as well. But first, we need to find the least common fator for 2/3 and 1/4 which is twelve which would be 8/12+3/12 which is 11/12 and 11/12 dividing by 1/2 is 22/12 since all you need to do is do the keep change flip method which would give you an answer of 1 10/12 or 1 5/6

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What is the name of the platonic solid shown below?
Leni [432]

Answer:

Since the part we can see is half of the whole figure, and there are six sides then in total there are 12 sides. A "12-gon" is called a dodecahedron. This is the answer.

8 0
3 years ago
Let the function f(x) have the form fx) = Acos(x+C). To produce a graph that matches the one shown below, what must the value of
slava [35]

Answer:

B. 4

Step-by-step explanation:

The given function is of the form:

f(x) = A \cos(x+C).

A is called the amplitude of the given function.

We can read from the graph that, the function ranges between:

-4 and 4

This implies that:

|A| = 4

Therefore the amplitude of the function is 4.

Hence the value of A must be 4.

8 0
4 years ago
____% of $4 = $3<br> Find the percentage
svetlana [45]
I believe the answer is 75 I am not sure but I adds up because 4*.75 equals to 3 there is another way to solve this though we can do the is over of equals % over 100 then we still get three have a nice day and good luck on your assignment (:
6 0
3 years ago
What is 7000 out of 1/10 is
Ann [662]

Answer:

70,000.

Step-by-step explanation:

7000 is (1/10) of 70,000 - as 7000*10=70,000.

Hope is help ba bye!

-  miah

8 0
3 years ago
Read 2 more answers
Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.
sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

  1. All the sides of the rhombus are congruent:  |DG|\cong |GF| \cong |EF| \cong |DE|
  2. The diagonals are perpendicular

Using the distance formula; d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}

\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}

|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}

\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}

|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}

\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}

|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}

\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}

Using the slope formula; m=\frac{y_2-y_1}{x_2-x_1}

The slope of EG is m_{EG}=\frac{2c-0}{0-0}

\implies m_{EG}=\frac{2c}{0}

The slope of EG is undefined hence it is a vertical line.

The slope of  DF is m_{DF}=\frac{c-c}{a+b-(-a-b)}

\implies m_{DF}=\frac{0}{2a+2b)}=0

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since |DG|\cong |GF| \cong |EF| \cong |DE| and DF \perp FG , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is m_{DE}=\frac{2c-c}{0-(-a-b)}

m_{DE}=\frac{c}{a+b)}

The slope of FG is m_{FG}=\frac{c-0}{a+b-0}

\implies m_{FG}=\frac{c}{a+b}

5 0
3 years ago
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