Rewrite the equations of the given boundary lines:
<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1
<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4
<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2
<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5
This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.
Compute the Jacobian determinant for this change of coordinates:

Rewrite the integrand:

The integral is then

A= h•w
6+2 = 8 feet long
4.5+1.5= 6 feet wide
8*6= 48 ft
Answer: 48 feet
Answer:
AB = 35
Step-by-step explanation:
For the value of variable z....;
;Perimetre = 132
; 132 = 2(4z + 3) + 2(5z)
; 132 = 8z + 6 + 10z
; 132 - 6 = 8z + 10z
; 126 = 18z
;the value of...z = 7
Therefore the value of length AB;
AB = 5z...then substitute the value of z into the length of AB
; AB = 5(7)
;AB = 35
1. C
2. B
3. B
I hope this helped!
Answer:
hii there
the correct answer is option ( C ) to the right
Step-by-step explanation:
hope it helps
have a nice day : )
and sorry also