PLEASE HELP ME PLEASE

Picture is shown above suppose that y varies directly with x, and y=12 when x=15

a_sh-v [17]

Step-by-step explanation:

Since y is directly proportional to x,

we have y = kx, where k is a real constant.

When x = 15, y = 12.

=> (12) = k(15), k = 0.8.

Therefore we have y = 0.8x.

When x = 2, y = 0.8(2) = 1.6.

The answer is y = 1.6 when x = 2.

7 0

3 years ago

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A computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

(a) Two computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 2 computers

r = number of success = both 2

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=2, p=0.94)$

Now, Probability that both computers are ancient is given by = P(X = 2)

P(X = 2) = $\binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}$

= $1 \times 0.94^{2} \times 1$

= 0.8836

(b) Eight computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = all 8

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=8, p=0.94)$

Now, Probability that all eight computers are ancient is given by = P(X = 8)

P(X = 8) = $\binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}$

= $1 \times 0.94^{8} \times 1$

= 0.6096

(c) Here, also 8 computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = at least one

p = probability of success which is now the % of computers

that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

LET X = Number of computers classified as cutting dash edge

So, it means X ~ $Binom(n=8, p=0.06)$

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X $\geq$ 1)

P(X $\geq$ 1) = 1 - P(X = 0)

= $1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}$

= $1 - [1 \times 1 \times 0.94^{8}]$

= 1 - $0.94^{8}$ = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0

3 years ago

Evaluate the expression when a= 2. a? +27

Troyanec [42]

Since a equals 2, 2 plus 27 is equal to 29. So your answer is 29. Hope that helped:)

7 0

4 years ago

9 students volunteer for a committee. How many different 7-person committees can be chosen?

lorasvet [3.4K]

If order doesn't matter (e.g. all the positions in the committee are essentially identical) then the number of possible choices is $\dbinom97=\dfrac{9!}{7!(9-7)!}=36$ .

7 0

3 years ago

Sambriddhi bent a rope to form a circle.If she got the circumference of the circle is 30cm more than its diameter. What was the

ivanzaharov [21]

easy peasy here we go..

so first circumference = 2π R

now it is given that circumference - 30 cm = Diameter;

Diameter = 2πR - 30 = 2 R { diameter = 2 times Radius}

now solving equations:

2πR -2R = 30

πR - R = 15

R ( π - 1 ) = 15

R ( 22/7 - 1) = 15

R ( 15/7 ) = 15

R = 15 x 7 / 15

R = 7 cm

Mark as brainliest

5 0

2 years ago

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