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3 years ago

Find the slope of the line that passes through each pair of points (13,-3),(-5,-5)

Mathematics

1 answer:

PIT_PIT [208]3 years ago

3 0

Answer:

$\boxed{\bold{\frac{1}{9} }}$

Explanation:

(13,-3), (-5,-5)

Find The Slope:

$\bold{\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}}$

$\bold{\left(x_1,\:y_1\right)=\left(13,\:-3\right),\:\left(x_2,\:y_2\right)=\left(-5,\:-5\right)}$

$\bold{m=\frac{-5-\left(-3\right)}{-5-13}}$

$\bold{ \ m \ = \ \frac{1}{9} }$

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a cylinder has radius 1.6 meters. it’s volume is 95 cubic meters. find it’s height to the nearest tenth of a meter

erastova [34]

H = 11.81 m

v= π r2 h

h = v/ π r2 = 95/ π 1.6(2)* = 11.81228m or just 11.81

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6 0

3 years ago

Help. What’s the answer to this problem?

liq [111]

Answer:

C) Yes, it’s a reflection over line f.

Step-by-step explanation:

It’s a reflection over line f.

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2 years ago

A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0

2 years ago

A. -10+(+10) b.-13+(-13) c. -11 + 0

DochEvi [55]

A is 0
B is-26
C is -11

5 0

3 years ago

Read 2 more answers

A quality-control inspector is testing a batch of printed circuit boards to see wheater they are capable of performing in a high

avanturin [10]

Answer:

see explaination

Step-by-step explanation:

Here the null hypothesis is that the PCB survives against the alternate that the PCB 'does not survive'. The test says that the PCB will survice if it is classified as 'good'; or, it will not survive if it is classifies as 'bad'.

a. The Type II error is the error committed when a PCB which cannot actually survive is classified as 'good'.

b. Therefore P(Type II error) = P(The PCB is classified as 'good' | PCB does not survives) = 0.03.

6 0

3 years ago