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Sergeeva-Olga [200]
3 years ago
11

Find the slope of the line that passes through each pair of points (13,-3),(-5,-5)

Mathematics
1 answer:
PIT_PIT [208]3 years ago
3 0

Answer:

\boxed{\bold{\frac{1}{9} }}

Explanation:

(13,-3), (-5,-5)

<u>Find The Slope:</u>

<u />\bold{\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}}<u />

<u />\bold{\left(x_1,\:y_1\right)=\left(13,\:-3\right),\:\left(x_2,\:y_2\right)=\left(-5,\:-5\right)}<u />

<u />\bold{m=\frac{-5-\left(-3\right)}{-5-13}}<u />

<u />\bold{ \ m \ = \ \frac{1}{9} }<u />

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Shawn sells 36 vehicles in 4 weeks. Brett sells 56 vehicles in 7 weeks. Who sells more vehicles per week?
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Answer:

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Step-by-step explanation:

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Answer:

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2 years ago
Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than
Fittoniya [83]
Inequation 1: 

\frac{2}{3}x-3 \geq y

to plot the pairs (x, y) for which the inequation holds, draw the line y=\frac{2}{3}x-3

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2: 

y+ \frac{2}{3}x\ \textless \ 4

y\ \textless \ - \frac{2}{3} x+ 4&#10;


draw the lines 

i)  y=\frac{2}{3}x-3          use points (0, -3),  (3, -1)

ii)y=- \frac{2}{3} x+ 4       use points ( 0, 4),   (3, 2)


let's use the point P(3, 3) to see what region of the lines need to be coloured:

\frac{2}{3}x-3 \geq y  ; 
\frac{2}{3}(3)-3 \geq 3
2-3 \geq 3, not true so we color the region not containing this point


y+ \frac{2}{3}x\ \textless \ 4
(3)+ \frac{2}{3}(3)\ \textless \ 4
3+ 5\ \textless \ 4 not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.



4 0
3 years ago
B A pair of fair dice is rolled, If the sum of the spots is 7, determine the probability that one di showed a 2.
finlep [7]

Answer:

\text{Probability}=\frac{1}{3}

Step-by-step explanation:

Given : A pair of fair dice is rolled, If the sum of the spots is 7.

To find : Determine the probability that one die showed a 2 ?

Solution :

A pair of fair dice is rolled the outcomes are,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

The sum of the spots is 7 i.e. (4,3),(2,5),(5,2),(3,4),(1,6),(6,1).

Total possibility = 6

Favorable outcome is that one die showed a 2 i.e. (2,5),(5,2)= 2

The probability that one die showed a 2 is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{2}{6}

\text{Probability}=\frac{1}{3}

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Answer:

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Step-by-step explanation:

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and the standard deviation \sigma is:

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We calculate the Z-score for X =65

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So

P(X

Looking in the table for the standard normal distribution we have to:

P(Z.

Finally the amount N of Labrador retrievers that weigh less than 65 pounds is:

N = P(X

N = 0.8413*5400

N= 4543 Labrador retrievers

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