All categories

3 years ago

PLEASE HELP!

Mathematics

2 answers:

hammer [34]3 years ago

6 0

Answer:

A = 16

Step-by-step explanation:

Taken together, the triangles form a square whose side length is 4. The area is ...

A = s² = 4²

A = 16

Colt1911 [192]3 years ago

3 0

Answer:

A= 16

Step-by-step explanation:

In the given figure , there are two triangles.

Side length and height of the triangle is the radius of the circle

Side length of the triangle = 4

height of the triangle = 4

Area of the triangle = $\frac{1}{2}*base*height$

= $\frac{1}{2}*4*4=8$

Area of another triangle = 8

Combined area of the triangle = 8+8 = 16

A= 16

You might be interested in

Natalie completed 87 sit-ups in 3 minutes, how many sit-ups would she complete in 5 minutes?

balu736 [363]

Answer:

145

Step-by-step explanation:

If she did 87 sit-ups in 3 minutes then we would divide 87 by 3 so we know how many sit ups in each minute.

87 divided by 3 is 29

since we want to know how much she would complete in 5 minute we would have to multiply 29 by 5

29x5=145

hope that answers ur question

6 0

3 years ago

Here is the question...

Rom4ik [11]

Cos60 degrees=1/2, so AK/AB=1/2. Since AK=KD, AK=1/2AD=1/2AB. Therefore, AB=AD. This is a rhombus, with four equal sides. Triangle ABK is congruent to triangle DBK (SAS), since AK=KD, angle AKB=angle BKD=90, and BK=BK. Therefore, BD=AB. The sum of four side lengths is 24. Each side length is equal to 24/4=6. BD=6.

7 0

3 years ago

Read 2 more answers

Solve for a. a+(−5)=−12 a=−17 a=−7 a = 7 a = 17

taurus [48]

A= negative seven because inverse operations of 5 so yeah

5 0

3 years ago

Certo número de caixas foi colocado em uma balança. Cada caixa tem o mesmo peso de 1,5kg. Se a balança marcou 24 kg, quantas cai

777dan777 [17]

Answer:

hanap ka sarili mong sagot bubu ka

3 0

3 years ago

C(x)=x^3-2x^2+8x+50. find the critical numbers

sattari [20]

$\large\begin{array}{l} \textsf{Finding the critical points of a given function:}\\\\ \mathsf{C(x)=x^3-2x^2+8x+50}\\\\\\ \bullet~~\textsf{1}\mathsf{^{st}}\textsf{ step: Find the derivative of C(x):}\\\\ \mathsf{C'(x)=(x^3-2x^2+8x+50)'}\\\\ \mathsf{C'(x)=3x^{3-1}-2\cdot 2x^{2-1}+8\cdot 1+0}\\\\ \mathsf{C'(x)=3x^2-4x+8} \end{array}$

$\large\begin{array}{l} \bullet~~\textsf{2}\mathsf{^{nd}}\textsf{ step: Solve the equation } \mathsf{C'(x)=0:}\\\\ \mathsf{3x^2-4x+8=0}\quad\Rightarrow\quad\begin{cases}\mathsf{a=3}\\\mathsf{b=-4}\\\mathsf{c=8} \end{cases}\\\\ \mathsf{\Delta=b^2-4ac}\\\\ \mathsf{\Delta=(-4)^2-4\cdot 3\cdot 8}\\\\ \mathsf{\Delta=16-96}\\\\ \mathsf{\Delta=-80$

$\large\begin{array}{l} \textsf{Since the discriminant is a negative number, there's no}\\\textsf{real solution for }\mathsf{C'(x)=0.}\\\\\\ \textsf{Therefore, }\mathsf{C(x)}\textsf{ doesn't have any critical point.} \end{array}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2150969

$\large\textsf{I hope it helps.}$

Tags: critical points numbers function derivative differential calculus

4 0

3 years ago