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solong [7]
4 years ago
9

Find the mean and median of the data set 3,5,6,2,10,9,7,5,11,6,4,2,5,4

Mathematics
2 answers:
Tanya [424]4 years ago
8 0

Answer:

mean: 5.6 ; median: 5

Step-by-step explanation:

first order them:

2, 2, 3, 4, 4, 5, 5, 5, 6, 6, 7, 9, 10, 11

now we can see that the median is 5 since it's in the middle

and the mean is adding all and dividing by how many numbers we have (AKA 14) so 2+2+3+4+4+5+5+5+6+6+7+9+10+11 = 79 and now we divide 79 by 14 which is:

5.64285714

Oxana [17]4 years ago
3 0

Answer:

the median is 5 while the mean is 5.6923076923077.

Step-by-step explanation:

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2/5 of the fish in a tank are guppies. 1/4 of the guppies are red. what fraction of the fish in the tank are red guppies.
Sholpan [36]

multiply 2/5 by 1/4

2/5 * 1/4 = 2/20 =  1/10 of the fish are red guppies

3 0
3 years ago
Evaluate the expression below by correctly ordering the steps.
Alex Ar [27]

Answer:

34

Step-by-step explanation:

= 9*4+(20-22)

= 9*4+(-2)

= 9*4+-2

= 9*4-2

= 36-2

= 34

4 0
3 years ago
Read 2 more answers
Based on the census data, the population of whoville was 43,230 in the year of 2000 and has been growing at a rate of 3.5%
kramer
The model would take the form of

P(t)=P(0)e^{0.035t}

So in 2015, when t=15, the population would be

P(15)=43230e^{0.035\times15}\approx73079

On the other hand, you could use the following discrete model for the population, which gives a similar result. If t=0 corresponds to the year 2000, then in 2001, when t=1, you have

P(1)=P(0)\times1.035^1\approx44743

In the next year,

P(2)=P(1)\times1.035^1=P(0)\times1.035^2\approx46309

And so on, making the general pattern for the tth year to be

P(t)=P(t-1)\times1.035^1=P(t-2)\times1.035^2=\cdots=P(0)\times1.035^t

This means in the year 2015, or when t=15, the population should be approximately

P(15)=P(0)\times1.035^{15}\approx72425
8 0
3 years ago
Marlene only has enough ingredients to make a 1/4 batch of cookies. For the smaller batch, she only needs 2/3 cup of sugar. How
Art [367]

Answer:

A full batch of cookies will require \hspace{0.15cm} \frac{8}{3} cup \hspace{0.15cm}of\hspace{0.15cm} \hspace{0.15cm} sugar,\hspace{0.15cm} or \hspace{0.15cm}2\hspace{0.15cm}whole\hspace{0.15cm} cups\hspace{0.15cm} and \hspace{0.15cm} \frac{2}{3} cup\hspace{0.15cm} of \hspace{0.15cm}sugar.

Step-by-step explanation:

i) \hspace{0.15cm}\frac{1}{4} batch \hspace{0.15cm}of \hspace{0.15cm}cookies\hspace{0.15cm} requires\hspace{0.15cm} \frac{2}{3} cup \hspace{0.15cm}of\hspace{0.15cm} sugar

ii) multiplying the above by 4 we get

\hspace{0.15cm}(4\times\frac{1}{4}) batch \hspace{0.15cm}of \hspace{0.15cm}cookies\hspace{0.15cm} requires\hspace{0.15cm}( 4 \times\frac{2}{3} )cup \hspace{0.15cm}of\hspace{0.15cm} sugar

iii) Therefore \hspace{0.15cm}1 batch \hspace{0.15cm}of \hspace{0.15cm}cookies\hspace{0.15cm} requires\hspace{0.15cm} \frac{8}{3} cup \hspace{0.15cm}of\hspace{0.15cm} sugar

iv) Therefore a full batch of cookies will require \hspace{0.15cm} \frac{8}{3} cup \hspace{0.15cm}of\hspace{0.15cm} \hspace{0.15cm} sugar,\hspace{0.15cm} or \hspace{0.15cm}2\hspace{0.15cm}whole\hspace{0.15cm} cups\hspace{0.15cm} and \hspace{0.15cm} \frac{2}{3} cup\hspace{0.15cm} of \hspace{0.15cm}sugar.

6 0
3 years ago
What conclusion can be drawn by observing that 30 is to the right of 10 on a
enyata [817]

The correct answer is B. 30 > 10

Explanation:

In mathematics and related fields, number lines are straight lines that display numbers using intervals this is useful to represent quantities visually, for example in graphs. Additionally, in number lines, numbers are organized in ascending order from left to right, for example, number 1  will be placed to the left of number 2. According to this, number 30 placed to the right of 10 will represent a higher quantity, considering the more you go to the right the higher the number is. Thus, 30 is greater than 10 (30 > 10).

8 0
4 years ago
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