Answer: a) What is a good scale to use for the y axis? -20 units.
(b) What is a good interval to use for the y axis?- 20 units
Step-by-step explanation:
A family is tracking its spending habits. Over the
past year, the grocery bill has ranged from $120 to $180.
We need to plot these points on a coordinate grid.
If we plot the grocery bills along the y-axis, and past years will be plotted along the x-axis.
So, a) Good scale to use for the y-axis will be
1 scale = 20 units
As 120 and 180 are both divisible by 20.
So, it will be a good scale to use for the y-axis.
b) Good interval to use for the y-axis:
It will be again of 20 units.
So subtract the diffference of 20 and 13 from 70
so first we find the difference and then subtract that from 70
use parenthases so
difference of 20 and 13 is equal to (20-13)
subtract that from 70
70-(20-13)
so you would do the pemdas and get 7 for the inside parethasees then do
70-7=63
equation is 70-(20-13)
Answer:
-13
- 
+ 4p + 3
Step-by-step explanation:
I am having a little trouble reading the number. I think 5 is the question number and not part of the problem. I think this is the problem:
(4p - 6 - 3) - (8
+ 7 - 6) You take the opposite of everything inside the second set of parentheses. You can think of it as multiplying through by -1
4p - 6 - 3 - 8 - 7 + 6 Now we combine like terms. That is the numbers with the same variable p and the same power of p.
-13 - 8 + 4p + 3
Answer:
-5
Step-by-step explanation:
f(2) = 2 * f(2-1) + 1
f(2) = 2 * f(1) + 1
f(2) = 2(-3) + 1
f(2) = (-6) + 1
f(2) = -5
The first choice is the correct answer. Note that for S(t) = 5t/(t+1):At t = 0, S = 0At t = 1, S = 5(1/2)At t = 2, S = 5(2/3)And as t increases, S approaches 5. (The pattern 1/2, 2/3, 3/4...gets closer and closer to 1).
