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3 years ago

IF YOU DONT KNOW THE ANSWER DONT ANSWER I NEED AN A ON THIS IN ORDER TO PASS MATH SO PLS HELP IF YOU CAN IF NOT DONT

Mathematics

1 answer:

saul85 [17]3 years ago

5 0

Answer:

1) 2019

2) 120-50=70

3) 2018

4) 100

5) 2018

6) 120-80=40

7) 2018

Step-by-step explanation:

1) 2019

2) 120-50=70

3) 2018

4) 100

5) 2018

6) 120-80=40

7) 2018

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Solve the given inequality :

tigry1 [53]

Answer:

x < -5 or x = 1 or 2 < x < 3 or x > 3

Step-by-step explanation:

Given rational inequality:

$\dfrac{(x-1)^2(x-2)^3}{(x^2-5x+6)^2(x+5)}\geq 0$

$\textsf{Factor }(x^2-5x+6):$

$\implies x^2-2x-3x+6$

$\implies x(x-2)-3(x-2)$

$\implies (x-3)(x-2)$

Therefore:

$\dfrac{(x-1)^2(x-2)^3}{(x-3)^2(x-2)^2(x+5)}\geq 0$

Find the roots by solving f(x) = 0 (set the numerator to zero):

$\implies (x-1)^2(x-2)^3=0$

$\implies (x-1)^2=0\implies x=1$

$\implies (x-2)^3=0 \implies x=2$

Find the restrictions by solving f(x) = undefined (set the denominator to zero):

$\implies (x-3)^2(x-2)^2(x+5)=0$

$\implies (x-3)^2=0 \implies x=3$

$\implies (x-2)^2=0 \implies x=2$

$\implies (x+5)=0 \implies x=-5$

Create a sign chart, using closed dots for the roots and open dots for the restrictions (see attached).

Choose a test value for each region, including one to the left of all the critical values and one to the right of all the critical values.

Test values: -6, 0, 1.5, 2.5, 4

For each test value, determine if the function is positive or negative:

$f(-6)=\dfrac{(-6-1)^2(-6-2)^3}{(-6-3)^2(-6-2)^2(-6+5)}=\dfrac{(+)(-)}{(+)(+)(-)}=+$

$f(0)=\dfrac{(0-1)^2(0-2)^3}{(0-3)^2(0-2)^2(0+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-$

$f(1.5)=\dfrac{(1.5-1)^2(1.5-2)^3}{(1.5-3)^2(1.5-2)^2(1.5+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-$

$f(2.5)=\dfrac{(2.5-1)^2(2.5-2)^3}{(2.5-3)^2(2.5-2)^2(2.5+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+$

$f(4)=\dfrac{(4-1)^2(4-2)^3}{(4-3)^2(4-2)^2(4+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+$

Record the results on the sign chart for each region (see attached).

As we need to find the values for which f(x) ≥ 0, shade the appropriate regions (zero or positive) on the sign chart (see attached).

Therefore, the solution set is:

x < -5 or x = 1 or 2 < x < 3 or x > 3

As interval notation:

$(- \infty,-5) \cup x=1 \cup (2,3) \cup(3,\infty)$

4 0

2 years ago

I need to find x for these

Ludmilka [50]

Answer:

1. x = 2

2. x = -2

3 x = 1

Step-by-step explanation:

Make x the subjects and work from there

3 0

3 years ago

Can some do this plzz

AleksAgata [21]

Answer:

$\frac{x+7}{x-3}$

Step-by-step explanation:

When you factor each equation, you result in two of the factors canceling out, resulting in $\frac{x+7}{x-3}$ .

[Top Equation]

The middle number is 3 and the last number is -28.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get 3

Multiply together to get -28

Can you think of the two numbers?

Try -4 and 7:

-4+7 = 3

-4*7 = -28

Fill in the blanks in

(x+_)(x+_)

with -4 and 7 to get...

(x-4)(x+7)

[Bottom Equation]

The middle number is -7 and the last number is 12.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -7

Multiply together to get 12

Can you think of the two numbers?

Try -3 and -4:

-3+-4 = -7

-3*-4 = 12

Fill in the blanks in

(x+_)(x+_)

with -3 and -4 to get...

(x-3)(x-4)

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3 years ago

If m 4 = (3x + 7) , and m 5 = (9x 43) , find m UPS.

IRISSAK [1]

Can you be more specific pls

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3 years ago

If f(x)=(x+6)(x−3)/(x−2), then calculate f(5). Round answers to two decimal places.

Marina CMI [18]

Step-by-step explanation:

f(5)=(5+6)(5-3)/(5-2)

=11(2)/3

=22/3

=7.33

5 0

3 years ago