Answer:
Step-by-step explanation:
One way to determine if the equation has any real solutions is to look at its discriminant. For the equation ax²+bx+c = 0, the discriminant is ...
d = b² -4ac
When the discriminant is negative, both solutions to the quadratic are complex. There are no real solutions in that case.
We can find the discriminant values to be ...
A: d = 2² -4(1)(4) = -12 . . . . no real zeros
B: d = 0² -4(3)(-5) = 60 . . . two real zeros
C: d = 8² -4(-2)(0) = 64 . . . two real zeros
D: d = 10² -4(1)(26) = -4 . . .no real zeros
Expressions A and D have no real zeros.
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<em>Comment on the question</em>
You are given an <em>expression</em>, not an <em>equation</em>. There is no equal sign. Hence, we cannot talk about <em>solutions</em>. We can only talk about <em>zeros</em>, values of x that make the expression have a value of zero.
Answer:
n=-16
Step-by-step explanation:
Add 4 on each side:
n/2 = -12+4
n/2 = -8
Multiply 2 on each side:
n=-16
Answer:
26.25
Step-by-step explanation:
you just need to count dots on the pencil
8/9 x 3/5 = 24/45
24/45 is your answer
hope this helps :D
Answer:
B.
(3x + 4)(x − 7)
Step-by-step explanation:
If you multiply.
3x2-21x+4x-28
3X2-17x-28
