It’s false because, a system of linear equations has one solution when the graphs intersect at a point.
In this situation, you have:
The mode is 79 (that’s the most common number).
The median is 78.5 (the middle value or the average of the two middle values, since there is an even number of test scores).
The mean is less than both of those, as it was brought down by the few scores of 49.
The means the mean will be less than median.
Answer: C
For the mix you need 60 Ib of nuts and raisins, and 60 lb of mix will sell for $300.
Let <em>x</em> be the weight of nuts and <em>y</em> the weight of raisins needed for the mix.
Total weight = <em>x</em>+<em>y</em> = 60, so <em>y</em> = 60 - <em>x</em>
Total value = 6<em>x</em> + 3<em>y</em> = 300. From the above, we can substitute the <em>y</em> for 60 - x:
Total value = 6<em>x</em> + 3(60 - <em>x</em>) = 300, which we can simplify to:
6<em>x</em> + 180 - 3<em>x</em> = 300, and simplify again to:
3<em>x</em> = 120, and again to:
<em>x</em> = 40. We can now calculate<em> y</em> from the first equation y = 60 - <em>x</em>, so:
y = 20.
40 lb of nuts and 20 lb of raisins. Check:
40 lb x $6/lb = $240, and 20 lb x $3/lb = $60, $240 + $60 = $300.
<span>Area of smaller=4*5=20 sq ft
Area of larger=4*6=24 sq ft
Larger is 4 more than smaller</span>
I’m gonna bet on D. Since I answered your question. Break my ankles✨
