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jonny [76]
2 years ago
5

Nancy found that x=1 is one solution to the quadratic eqaution (x+2)2=a.What is the Value of a ?

Mathematics
2 answers:
horrorfan [7]2 years ago
8 0
Insert 1 into your equation (1+2)2=a  1+2=3 and 3X2=6 so therefore a=6
 
coldgirl [10]2 years ago
6 0
<span>(x + 2)</span>·<span>2 = a

(1 + 2)</span>·2 = a

3·2 = a

a = 6
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Answer:

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<em>AND</em><em> </em><em>PLS</em><em> </em><em>FOLLOW</em>

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What else would need to be congruent to show that JKL= MNO by AAS?
taurus [48]
Answer: Choice B) Angle L = Angle O

---------------------------------------------------
---------------------------------------------------

If we know that Angle L is congruent to Angle O, then we can use the AAS (angle angle side) congruence property. We have one pair of angles marked by the square marker (angle J and angle M). So they are congruent angles. We have a pair of congruent sides JK = MN = 3. So we're just missing a pair of angles. 

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3 0
3 years ago
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Which is a factor of the polynomial f(x) = 6x4 – 21x3 – 4x2 + 24x – 35?
QveST [7]
<span>I note that this problem starts out with "Which is a factor of ... "  This implies that you were given several answer choices.  If that's the case, it's unfortunate that you haven't shared them.

I thought I'd try finding roots of this function using synthetic division.  See below:

f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation.  Thanks.

Possible zeros of this poly are factors of 35:  plus or minus 1, plus or minus 5, plus or minus 7.  Use synthetic division; determine whether or not there is a non-zero remainder in each case.  If none of these work, form rational divisors from 35 and 6 and try them:  5/6, 7/6, 1/6, etc.

Provided that you have copied down the function 
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By graphing this function, I found that the graph crosses the x-axis at 7/2.  There is another root.

Using synth. div. to check whether or not 7/2 is a root:

         ___________________________
7/2   /   6    -21    -4    24    -35
                   21      0   -14     35           
        ----------- ------------------------------
           6        0     -4    10       0

Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial.  Thus, (x-3.5), or (x-7/2), is a factor.

7 0
2 years ago
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wolverine [178]
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