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2 years ago

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Justin recently drove to visit his parents who live 300 miles away. On his way there his average speed was 11 miles per hour fas

ter than on his way home (he ran into some bad weather). If Justin spent a total of 10 hours driving, find the two rates.

1 answer:

Lynna [10]2 years ago

5 0

Answer:

x=1

Step-by-step explanation:

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mercury orbits the sun in 87 and 24/50 venus orbits the sun in 224 and 7/10 earthdays and mars orbits the sun in 686 and 49/50 d

slega [8]

Mercury: 87 24/25
Venus 224 7/10
Mars 686 49/50

All we need to do is to convert fractions so they have a denominator of 10, 100, 1000 etc.

87 24/25 = 87 96/100
224 7/10 stays the same
686 49/50 = 686 98/100

Now we can easily convert them into decimals:

Mercury: 87.96
Venus: 224.7
<span>Mars: 686.98</span>

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3 years ago

A rectangular pool has a length of

Sholpan [36]

P=(15x-2+4x+7)2=(19x+5)2=38x+10

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2 years ago

What is the multiplacation problem for sandy walk 26 miles in a month. If she were consistent in her walking for 2 years, how ma

Svetllana [295]

Answer:

624 miles

Step-by-step explanation:

We know that there are 12 months in a year, and you need to find out the total miles she walks in two years, which is 24 months.

So we multiply 26(24)

This is equal to 624 miles

6 0

3 years ago

Read 2 more answers

Help meeeeeeeeeeeeeeeeeee <br><br> >_

nignag [31]

Answer:

good news, the second one is relatively easy because it can be factored to (2x+1)(2x-3) which means that number two has solutions of -1/2 and 3/2

but for number one you have to either use the quadratic equation cause I've tried using synthetic division or just use the second equation to derive the first solutions so I tried move the graph up by two units and found that the intercepts are approximately (1+-√2)/2 or 1/2+-1/√2 for 4x^2-4x-1

7 0

3 years ago

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exa

yarga [219]

Answer:

$z= \frac{85-70}{10}=1.5$

$z= \frac{45-35}{5}=2$

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

Step-by-step explanation:

Assuming this complete question:

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exams were scored on different scales. Remembering what he learned about the advantages of Z scores, he asks his friend for the mean and standard deviation of her class on the exam, as well as her final exam score. Here is the information:

Our student: Final exam score = 85; Class: M = 70; SD = 10.

His friend: Final exam score = 45; Class: M = 35; SD = 5.

The Z score for the student and his friend are:

A) Our student, Z= -1.07; his friend, Z= -1.14.

B) Our student, Z= 1.50; his friend, Z=2.00.

C) Our student, Z= 1.07; his friend, Z= -1.14.

D) Our student, Z= 1.07; his friend, Z= 1.50

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution

Let X the random variable that represent the scores for our student, and for this case we know that:

$E(X)= \mu =70, SD_X=\sigma=10$

The z score is given by:

$z=\frac{x-\mu}{\sigma}$

If we use this we got:

$z= \frac{85-70}{10}=1.5$

Let Y the random variable that represent the scores for his friend, and for this case we know that:

$E(Y)= \mu =35, SD_Y=\sigma=5$

The z score is given by:

$z=\frac{y-\mu}{\sigma}$

If we use this we got:

$z= \frac{45-35}{5}=2$

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

3 0

3 years ago