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3 years ago

Can someone please help its my last one

Mathematics

1 answer:

Greeley [361]3 years ago

7 0

Answer:

80 + 40 + (x + 64) = 180

120 + (x + 64) = 180

-120 -120

x + 64 = 60

-64 -64

X = -4

Step-by-step explanation:

Let's double check

64 - 4 = 60

60 + 80 + 40 = 180 It works!

Therefore X = -4.

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What is adding 40 percent to 1540.00

Ludmilka [50]

Answer:

Addition but... 40/100x1540 = 616.00

Step-by-step explanation:

edit: i goofed

8 0

3 years ago

Read 2 more answers

What rule matches the function represented by the table?

Sliva [168]

Let's try a line

y = mx + b

From (0,4):

4 = 0x + b

b = 4

So far we have

y = mx + 4

From (1,1)

1 = m(1) + 4

-3 = m

Our rule is y = -3 x + 4

Let's check the other points:

-3(-4)+4 = 12+4 = 16 good

-3(4)+4 = -12+4 = -8 good

-3(9) + 4 = -23 good

Answer: y = -3 x + 4

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3 years ago

PLEASE HELP THIS IS A MULTIPLE CHOICE QUESTION !!!!

SOVA2 [1]

Answer:

c) subtraction property of order

Step-by-step explanation:

To get from line 1 to line 2, 3 was subtracted from both sides of the inequality. The "subtraction property of order" says you can do that without changing the order or the solution.

It should not be a surprise that when subtraction is involved, the associated property has "subtraction" in its name.

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4 years ago

Fluoxetine, a generic anti-depressant, claims to have, on average, at least 20 milligrams of active ingredient. An independent l

san4es73 [151]

Answer:

$t=\frac{18.7-20}{\frac{5}{\sqrt{80}}}=-2.326$

$df=n-1=80-1=79$

$p_v =P(t_{(79)}$

Step-by-step explanation:

Information given

$\bar X=18.7$ represent the sample mean for the content of active ingredient

$s=5$ represent the sample standard deviation for the sample

$n=80$ sample size

$\mu_o =20$ represent the value that we want to test

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean for the active agent is at least 20 mg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 20$

Alternative hypothesis: $\mu < 20$

The statistic would be:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Now we can calculate the statistic:

$t=\frac{18.7-20}{\frac{5}{\sqrt{80}}}=-2.326$

P value

The degrees of freedom are calculated like this:

$df=n-1=80-1=79$

Since is a one left tailed test the p value would be:

$p_v =P(t_{(79)}$

6 0

4 years ago

What expression is equivalent to ^3 square root of 2y^3 times 7 square root of 18y

Mumz [18]

Answer:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

Step-by-step explanation:

The question is poorly formatted.

Given

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

Required

Derive an equivalent expression

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

Express 18 as 9 * 2

$\sqrt[3]{2y^3} * 7\sqrt{9 * 2y}$

Split the expression as follows:

$\sqrt[3]{2y^3} * 7\sqrt{9} * \sqrt{2y}$

Take positive square root of 9

$\sqrt[3]{2y^3} * 7*3 * \sqrt{2y}$

$\sqrt[3]{2y^3} * 21 * \sqrt{2y}$

$21*\sqrt[3]{2y^3} * \sqrt{2y}$

The cube root can be rewritten to give:

$21*\sqrt[3]{2}*\sqrt[3]{y^3} * \sqrt{2y}$

$\sqrt[3]{y^3} = y^{3*\frac{1}{3}} = y$

So, we have:

$21*\sqrt[3]{2} * y * \sqrt{2y}$

Rewrite as:

$21y *\sqrt[3]{2} * \sqrt{2y}$

Split $\sqrt{2y$

$21y *\sqrt[3]{2} * \sqrt{2} * \sqrt{y}$

Collect Like Terms

$21y*\sqrt{y} *\sqrt[3]{2} * \sqrt{2}$

Represent in index form

$21y*y^{\frac{1}{2}} *2^\frac{1}{3} *2^\frac{1}{2}$

Apply law of indices

$21*y^{1+\frac{1}{2}} *2^{\frac{1}{3} +\frac{1}{2} }$

$21*y^{\frac{2+1}{2}} *2^{\frac{2+3}{6}}$

$21*y^{\frac{3}{2}} *2^{\frac{5}{6}}$

$21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

Hence:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

6 0

3 years ago