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Maru [420]
3 years ago
9

How do you write the equation of a line (in slope intercept form) with three given points?​

Mathematics
2 answers:
iris [78.8K]3 years ago
6 0
You only need two points to write the equation of a line.

Slope intercept form of a line is y=mx+b, where m is the slope and b is the y intercept.

I’m going to use the points (5,3) and (8,5) to show how to write the equation.

First, find the slope. The formula to find the slope is y2-y1/x2-x1. With my points, the slope equation would look like this:
m=(5-3)/(8-5)
m=2/3

I put this into my point slope formula
y=2/3x+b

To find out the b (y-intercept), I plug in one pair of points, then solve for b. I will use (5,3)

3=2/3(5)+b
3=10/3+b
-1/3=b

I can now add b to my equation, and get y=2/3x-1/3

To double check this, I could graph this line and make sure that it crosses my selected points. Hope this helps!
Mrrafil [7]3 years ago
3 0

With even just two points, you can find the equation of a line in slope-intercept form.

Slope-intercept form: y=mx+b where m is the slope and b is the y-intercept

<u>1) Solve for the slope (</u>m<u>)</u>

The equation to solve for the slope is m=\frac{y_2-y_1}{x_2-x_1} when the two points are (x_1,y_1) and (x_2,y_2). Plug the coordinates of these points into the equation and solve for m.

Then, plug m into y=mx+b.

<u>1) Solve for the y-intercept (</u>b<u>)</u>

Then, take any of the given points and plug it into y=mx+b along with the slope. Isolate b to get the y-intercept. Then, plug both m and b back into y=mx+b to get your final equation.

I hope this helps!

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Answer:

a) P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

b) P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

X \sim N(0.12,0.009)  

Where \mu=0.12 and \sigma=0.009

We are interested on this probability

P(0.11

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want this probability:

P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

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