Ask question

Ask question

All categories

3 years ago

8

Find the missing ANGLE Someone plsss helpppp!!! I’ll give brainliest!!! :(((

1 answer:

Romashka [77]3 years ago

6 0

The answer is triangle sum c is 74

You might be interested in

Pls help with linear equations!!!

artcher [175]

Answer:

266

Step-by-step explanation:

Let no. of main floor tickets = x

Balcony tickets = x + 100

4(x+100) + 12(x) = 3056

4x + 400 + 12x = 3056

16x = 3056-400

16x = 2656

x = 2656/16

x = 166

No. of Balcony tickets = x + 100 = 166 + 100 = 266

4 0

3 years ago

Read 2 more answers

Please explain how to find the answer

irina1246 [14]

Answer:

$\rm x=\frac{46}{3}$

$\rm y=-\frac{25}{24}$

Step-by-step explanation:

$\huge\begin{array} {|c|} \hline\left. \begin{cases} { \rm\frac{ 1 }{ 4 } x+ \frac{ 4 }{ 5 } y = 3 } \\ { \rm\frac{ 5 }{ 16 } x- \frac{ 1 }{ 5 } y=5 } \end{cases} \right. \\ \hline \end{array}$

$\\ \Large \overline{ \rm - \: Steps \: using \: substitution \: - }$

$\rm \frac{1}{4}x+\frac{4}{5}y=3$

$\rm \frac{1}{4}x=-\frac{4}{5}y+3$

$\rm x=4\left(-\frac{4}{5}y+3\right)$

$\rm x=-\frac{16}{5}y+12$

┈

$\rm \frac{5}{16}\left(-\frac{16}{5}y+12\right)-\frac{1}{5}y=5$

$\rm -y+\frac{15}{4}-\frac{1}{5}y=5$

$\rm -\frac{6}{5}y+\frac{15}{4}=5$

$\rm -\frac{6}{5}y=\frac{5}{4}$

$\bold{ y=-\frac{25}{24}}$

┈

$\rm x=-\frac{16}{5}\left(-\frac{25}{24}\right)+12$

$\rm x=\frac{10}{3}+12$

$\bold{ x=\frac{46}{3}}$

7 0

3 years ago

Read 2 more answers

Last spring, the drama department at Greenwood High School had 10 student audition for the musical. This spring, there were 8 st

Brilliant_brown [7]

20% cuz 2/10 students dropout then 2/10=20%

5 0

3 years ago

PLEASE HELP ME ON (A)

Liula [17]

It’s 4 ik know this it’s four cixhdhdud didjdhdh djdjdhd djdjdhd

3 0

3 years ago

Read 2 more answers

Which side lengths form a right triangle?

STALIN [3.7K]

Answer:

8, 15, 17 and $\sqrt{2} , \sqrt{2}, 2$

Step-by-step explanation:

$c=\sqrt{a^2+b^2}$

$33=/=\sqrt{5^2+\sqrt{8}^2 }$

$17=\sqrt{8^2+15^2}$

$2=\sqrt{\sqrt{2}^2+\sqrt{2}^2 }$

3 0

3 years ago