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3 years ago

What is 6+ 4 - 2 first to answer gets brainlist

Mathematics

2 answers:

sladkih [1.3K]3 years ago

7 0

Answer:8

Step-by-step explanation:

inysia [295]3 years ago

5 0

Answer:

Step-by-step explanation:

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A mechanic has a set fee for working on someone's automobile and charges by the hour for making repairs. The total cost of her s

julia-pushkina [17]

I think it’s either b or c. But I’m leaning more towards c

7 0

2 years ago

You want to estimate the mean amount of time college students spend on the Internet each month. How many college students must y

KonstantinChe [14]

Answer:

752.95

Step-by-step explanation:

Data provided in the question

The standard deviation of population = 210

The Margin of error = 15

The confidence level is 75%, so the z value is 1.96

Now the required sample size is

$= 1.96^2\times \frac{210^2}{15^2}$

= 752.95

Hence, the number of college students spends on the internet each month is 752.95

Simply we considered the above values so that the n could come

8 0

3 years ago

What does -3(n+5)=12 equal

Reil [10]

Answer:

n= -9

Step-by-step explanation:

-3 ( n+5 ) = 12

-3n - 15 = 12

-3n = 12+15

-3n = 27

n = -27/3

n = -9

6 0

3 years ago

10. What are the x and y intercepts of the equation --30 + 5y = 15

Dafna1 [17]

Answer:

i think you had written the formula wrongly

so if it was -30x not -30

Step-by-step explanation:

x intercept when y=0

-30x = 15

x= -0.5

y intercept when x=0

5y= 15

y=3

- if this is the one you want

-30 +5y=15

5y =45

y=9

and there not x intercept { }

4 0

3 years ago

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago