All categories

3 years ago

Help! Quick! Find the area of the composite figure

Mathematics

1 answer:

kirill [66]3 years ago

3 0

Answer:

60m

Step-by-step explanation:

To find the area of the triangle you multiply the base by height and divide by two, but we don’t know the base of the triangle!

Luckily, the bottom of the triangle is a rectangle. Rectangles are symmetrical, and the other side of the rectangle is 8.

So, the base of the triangle is 8.

Now let’s find the area of the triangle:

8 x 5 = 40

40/2 = 20

20 is the area of the triangle

Now, we must find the area of the rectangle!

The formula for rectangle area is just width x length:

8 x 5 = 40

Add them together:

40 + 20 = 60

Therefore, the area is 60m.

You might be interested in

Evaluate the Riemann sum for f(x) = 3 - 1/2 times x between 2 and 14 where the endpoints are included with six subintervals taki

Digiron [165]

Answer:

-6

Step-by-step explanation:

Given that :

we are to evaluate the Riemann sum for $f(x) = 3 - \dfrac{1}{2}x$ from 2 ≤ x ≤ 14

where the endpoints are included with six subintervals, taking the sample points to be the left endpoints.

The Riemann sum can be computed as follows:

$L_6 = \int ^{14}_{2}3- \dfrac{1}{2}x \dx = \lim_{n \to \infty} \sum \limits ^6 _{i=1} \ f (x_i -1) \Delta x$

where:

$\Delta x = \dfrac{b-a}{a}$

a = 2

b =14

n = 6

∴

$\Delta x = \dfrac{14-2}{6}$

$\Delta x = \dfrac{12}{6}$

$\Delta x =2$

Hence;

$x_0 = 2 \\ \\ x_1 = 2+2 =4\\ \\ x_2 = 2 + 2(2) \\ \\ x_i = 2 + 2i$

Here, we are using left end-points, then:

$x_i-1 = 2+ 2(i-1)$

Replacing it into Riemann equation;

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} \begin {pmatrix}3 - \dfrac{1}{2} \begin {pmatrix} 2+2 (i-1) \end {pmatrix} \end {pmatrix}2$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - (2+2(i-1))$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - (2+2i-2)$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 -2i$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 2i$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - 2 \lim_{n \to \infty} \sum \imits ^{6}_{i=1} i$

Estimating the integrals, we have :

$= 6n - 2 ( \dfrac{n(n-1)}{2})$

= 6n - n(n+1)

replacing thevalue of n = 6 (i.e the sub interval number), we have:

= 6(6) - 6(6+1)

= 36 - 36 -6

= -6

5 0

3 years ago

Find the height of the cone. 3*13.4*1.6^2*/3

Sunny_sXe [5.5K]

Answer:

the answer is 54.9928264451

4 0

3 years ago

-4.6+5.3 help please thank you are the best

fomenos

Answer:

0.7

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

*****Write a polynomial using the roots -3,5i. PLEASE HELP IM SO LOST!!!

Vladimir79 [104]

The polynomial $(x-a)$ has a unique root, $a$ , for any $a$ .

Hence $(x+3)(x-5i)$ is a polynomial with roots $-3$ and $5i$

8 0

3 years ago

How many solutions exist for the given equation? StartFraction one-half left-parenthesis x plus 12 right-parenthesis equals 4 x

Firlakuza [10]

Answer:

One solution x = 2

Step-by-step explanation:

Given the equation:

$\dfrac{1}{2}(x+12)=4x-1$

Multiply this equation by 2:

$2\cdot \dfrac{1}{2}(x+12)=2\cdot (4x-1)\\ \\x+12=2(4x-1)$

Use distributive property:

$x+12=8x-2$

Combine the like terms:

$x+12=8x-2\\ \\x+12-12=8x-2-12\\ \\x=8x-14\\ \\x-8x=8x-14-8x\\ \\-7x=-14\\ \\7x=14\\ \\x=2$

Thus, this equation has one solution x = 2

7 0

4 years ago

Read 3 more answers