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2 years ago

FINDDDD VALUE OF Z !!!!!

Mathematics

2 answers:

Vikentia [17]2 years ago

6 0

I can help you did you ask Siri?

Just take a picture on Siri the would lead you to the answer.

Step-by-step explanation:

I hope that helps please give me Brainliest

Tems11 [23]2 years ago

4 0

Z=9 hope this helps!!!

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Hi so could anyone please tell me how to solve this I’ve tried looking through my notes but I can’t find a question similar to t

neonofarm [45]

Answer:

no solution

Step-by-step explanation:

There are no values of x that make the equation true.

6 0

3 years ago

Shobos mother present age is six times shobos present age. Shobos age five from now will be one third of his mother's present ag

r-ruslan [8.4K]

Answer:

Step-by-step explanation:

From the problem statement, we can setup the following equations:

$M = 6S$

$S + 5 = \frac{1}{3}M$

where $S$ is the current age of Shobos and $M$ is the current age of his mother.

Substituting the first equation into the second will allow us to solve for $S$ :

$S + 5 = \frac{1}{3}M$

$S + 5 = \frac{1}{3}(6S)$

$S + 5 = 2S$

$S = 5$

Substituting this value into the first equation gives us the age of the mother:

$M = 6S$

$M = 6(5)$

$M = 30$

5 0

2 years ago

Read 2 more answers

The weight distribution of parcels sent in a certain manner is normal with mean value 17 lb and standard deviation 3.3 lb. The p

Yakvenalex [24]

Answer: The value of c would be 26.514 lb.

Step-by-step explanation:

Since we have given that

Mean = 17 lb

Standard deviation = 3.3 lb

At 99% level of significance, z = 2.58

So, it becomes,

$Z=\dfrac{X-\mu}{\sigma}\\\\2.58=\dfrac{X-17}{3.3}\\\\2.58\times 3.3=X-17\\\\8.514+17=X\\\\X=25.514$

So, the weight c would be

$c=25.514+1\\\\c=26.514$

Hence, the value of c would be 26.514 lb.

7 0

3 years ago

A line passes through the point (8,-7) and has a slope of -5/4.

AURORKA [14]

Answer:

8 7

Step-by-step explanation:

Because the number will be positive

4 0

2 years ago

Given that y=x^(1/3) , use calculus to determine an approximate value for ∛8030

Alex777 [14]

F(x) = x^(1/3)
f(8000) = 8000^(1/3) = 20

f'(x) = 1/3 * x^(-2/3)
f'(x) = 1/(3x^(2/3))
f'(8000) = 1/(3*8000^(2/3)) = 1/(3*400) = 1/1200

Linear approximation for f(x) about x = 8000
L(x) = f(8000) + f'(8000) (x−8000)
L(x) = 20 + 1/1200 (x−8000)

8030^(1/3) ≈ L(8030)
= 20 + 1/1200 (8030−8000)
= 20 + 30/1200
= 20 + 1/40
= 20.025

8 0

2 years ago